Inequalities 9 – h > 2; 6, 7, 8 show work please

1 answer:

5 0

Solving the inequalities, I am guessing?

9 - h > 2
-h > -7
Divide by -1, so you flip the sign
h < 7

9 - h > 6
-h > -3
Again, divide by -1, sign flips to les than
h < 3

9 - h > 7
-h > -2
h < 2

9 - h > 8
-h > -1
h < 1

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1. Find the product. Simplify. 13/14 of 10/9. A. 15/42 B. 5/21 C. 2/7 D. 5/6 2. Andy has 5 pots, and each pot can hold 3/8 pound

Rufina [12.5K]

1) Resultant fraction: $\frac{65}{63}$

2) Total soil: $1\frac{7}{8}$ pounds

3) Result of the product: $\frac{35}{2}$

Step-by-step explanation:

In this problem, we want to find the product between the two fractions

$\frac{13}{14}$

and

$\frac{10}{9}$

In order to find this product, we have to multiply the numerators of each fraction and the denominators of each fraction. We get:

$\frac{13}{14}\cdot \frac{10}{9}=\frac{13\cdot 10}{14\cdot 9}=\frac{130}{126}$

Now we simplify, dividing both numerator and denominator by 2:

$\frac{130/2}{126/2}=\frac{65}{63}$

And the fraction cannot be further simplified.

Here we have:

n = 5 (number of pots that Andy has)

$s=\frac{3}{8}$ (amount of soil (in pounds) that each pot can contain)

In order to find the amount of soil that Andy needs to fill all the pots, we have to multiply the number of pots (n) by the amount of soil that each pot can contain (s).

If we do so, we find:

$t=n \cdot s = 5 \cdot \frac{3}{8}=\frac{5\cdot 3}{8}=\frac{15}{8}$