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anastassius [24]
3 years ago
9

Find the value of y. Round to the nearest tenths place.

Mathematics
2 answers:
Usimov [2.4K]3 years ago
6 0
Are there any options on the test or homework
ale4655 [162]3 years ago
4 0

Answer:

y = 12

Step-by-step explanation:

Look at the left triangle first.  Opposite the 30 degree angle (not shown) is the shortest side, which (according to the sine function) is half the hypotenuse, or 2√3.  Then (2√3)² + x² = (4√3)², or

4(3) + x² = 16(3).  Thus, x² = 16(3) - 4(3) = 12(3) = 36, and so x = 6.  Again using the sine function, we find that x = 2y = 6, so, using the sine function, we find that sin 30° = 6/y.  Thus y = 6 / (2/1) = 12  =  y

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If sin x = 3/5, calculate tan x​
valkas [14]

Answer:

tan(x)=-+(3/4)

Step-by-step explanation:

3 0
3 years ago
A jeweler wants to combine a 60% gold alloy with a 20% gold alloy to make 1000 grams of 50% gold alloy. How many grams of 60% al
kramer

Answer:

750 grams of 60% alloy

Step-by-step explanation:

Define x = amount of 60% alloy and y = amount of 20% alloy

Equating the amounts of gold:

0.6x+0.2y = 1000(0.5)

Since there must be 1000 grams total:

x+y = 1000

Writing the 2 resulting equations together:

0.6x + 0.2y = 500

x + y = 1000

Multiply the first equation by 5:

3x + y = 2500

x + y = 1000

Subtracting the 2nd equation from the 1st:

2x = 1500

x = 750

Answer: 750 grams of 60% alloy

7 0
2 years ago
A truck weighing 150kN and travelling at 2m/sec impacts with a buffer
FrozenT [24]

The maximum compression of the spring is 0.276 m

Step-by-step explanation:

First of all, we calculate the spring  constant of the spring, by using Hooke's law:

F=kx

where

F = 10 kN = 10,000 N is the force applied

x = 1.25 cm = 0.0125 m is the corresponding compression of the spring

k is the spring constant

Solving for k,

k=\frac{F}{x}=\frac{10,000}{0.0125}=8\cdot 10^5 N/m

When the truck impacts with the spring, all the kinetic energy of the truck is converted into elastic potential energy of the spring, so we can write

\frac{1}{2}mv^2=\frac{1}{2}kx^2 (1)

where

m is the mass of the truck

v = 2 m/s is the initial speed of the truck

k=8\cdot 10^5 N/m is the spring constant

x is the compression of the spring

The mass of the truck can be found from its weight:

m=\frac{W}{g}=\frac{150,000 N}{9.81 N/kg}=15,290 kg

So now we can re-arrange eq.(1) to find the compression, x:

x=\sqrt{\frac{mv^2}{k}}=\sqrt{\frac{(15,290)(2)^2}{8\cdot 10^5}}=0.276 m

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

6 0
3 years ago
In the reaction 2HgO(s) --> 2Hg(l) + O2(g) we measure the evolution of gas to determine the rate of reaction. At the beginnin
djverab [1.8K]

Answer:

0.034 L/min

Step-by-step explanation:

The rate of reaction is the volume change (ΔV) divided by the time(t) and divided by the coefficient of the compound in the reaction. The coefficient of O₂ is 1, so:

R = (0.36 - 0.02)/10

R = 0.034 L/min

4 0
3 years ago
I need help I would really thank whoever answers this for me
Mars2501 [29]
To do these problems, you plug in the ‘n’ value given into the equation.

a. 6j - 3 : j = 4
6(4) - 3
24 - 3
21

b. 1/2b + 5 : b = 14
1/2(14) + 5
7 + 5
12

c. 8 + 4k : k = 3.5
8 + 4(3.5)
8 + 14
22
6 0
3 years ago
Read 2 more answers
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