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3 years ago

Describe the expression 2(m + 7)

Mathematics

2 answers:

Alex73 [517]3 years ago

6 0

Answer is A !!!!!!!!!!!!

lbvjy [14]3 years ago

4 0

Answer:

Step-by-step explanation:

Order of operations, parentheses first. when it says "two times THE SUM OF ...." it means you need to find the sum first, which you do. you should know that in math, when a number is next to a parentheses they get multiplied, which is what happens next, and there is nothing else to be done so A is you answer.

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Find the twenty-fifth term of an arithmetic sequence if the first term is-1 and the common difference is 5. Write the first thre

denis-greek [22]

Answer:

1). $T_{25}=119$

2). $T_{1}=-23$

$T_{2}=-23+2=-21$

$T_{3}=-23+4=-19$

Step-by-step explanation:

First term of an arithmetic sequence is (-1) and common difference is 5.

Then we have to find twenty fifth term of this arithmetic sequence.

Since explicit formula of an arithmetic sequence is represented by

$T_{n}=a+(n-1)d$

Where $T_{n}$ represents nth term of the sequence.

a = first term

n = number of term

and d = common difference

Now we will find 25th term of this sequence.

$T_{25}=(-1)+(25-1)5$

= (-1) + 120

= 119

Similarly in second part of this question we have to find first three terms of an arithmetic sequence in which

$T_{21}=17$ and

$T_{50}=75$

Now from the explicit formula

17 = a + (21 - 1)d

17 = a + 20d --------(1)

75 = a + (50 - 1)d

75 = a + 49d --------(2)

Now we subtract equation 1 from 2

75 - 17 = 49d - 20d

29d = 58

d = $\frac{58}{29}=2$

By putting d = 2 in equation 1

17 = a + 20×2

17 = a + 40

a = 17 - 40

a = -23

Therefore, first three terms of this sequence will be

$T_{1}=-23$

$T_{2}=-23+2=-21$

$T_{3}=-23+4=-19$

8 0

4 years ago

Consider w=sqrrt2/2(cos(225°) + isin(225°)) and z = 1(cos(60°) + isin(60°)). What is w+ z expressed in rectangular form?

SVETLANKA909090 [29]

Answer:

Option (3)

Step-by-step explanation:

w = $\frac{\sqrt{2}}{2}[\text{cos}(225) + i\text{sin}(225)]$

Since, cos(225) = cos(180 + 45)

= -cos(45) [Since, cos(180 + θ) = -cosθ]

= - $\frac{\sqrt{2}}{2}$

sin(225) = sin(180 + 45)

= -sin(45)

= - $\frac{\sqrt{2}}{2}$

Therefore, w = $\frac{\sqrt{2}}{2}[-\frac{\sqrt{2}}{2}+i(-\frac{\sqrt{2}}{2})]$

= $-\frac{2}{4}(1+i)$

= $-\frac{1}{2}(1+i)$

z = 1[cos(60) + i(sin(60)]

= $[\frac{1}{2}+i(\frac{\sqrt{3}}{2})$

= $\frac{1}{2}(1+i\sqrt{3})$

Now (w + z) = $-\frac{1}{2}(1+i)+\frac{1}{2}(1+i\sqrt{3})$

= $-\frac{1}{2}-\frac{i}{2}+\frac{1}{2}+i\frac{\sqrt{3}}{2}$

= $\frac{(i\sqrt{3}-i)}{2}$

= $\frac{(\sqrt{3}-1)i}{2}$

Therefore, Option (3) will be the correct option.

3 0

3 years ago

Read 2 more answers

What function is the inverse of the exponential function y = 3^x?

Tomtit [17]

Answer:

$y=\log_{3}(x)$

Step-by-step explanation:

To take the inverse of a function, swap x with y and vice versa. Therefore, the inverse of y = 3^x is x = 3^y. However, because we are being asked for a <em>function</em>, we have to rewrite this equation by isolating y. We do this with logarithms:

$x=3^y\\y = \log_{3}x$