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Sholpan [36]
3 years ago
15

Can someone help me with this

Mathematics
1 answer:
BartSMP [9]3 years ago
8 0

Answer:

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Calculate the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass of 1 m^3 of water to be 1000 kg
Lady bird [3.3K]

Answer:

1813.137 KJ

Step-by-step explanation:

potential energy of the body = mgH

where m is mass in Kg , g= 9.81 m/sec^2 and H= height in m

here m= 1000 kg, g= 9.81 m/s^2  and H= 607 feet = 607×0.305= 185.135 m

hence the potential energy p= 1000×9.81×185.135= 1813137.2 J

= 1813.137 KJ

hence the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass as 1000 kg is = 1813.137 KJ

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21,400 in standard form
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Answer:

2.14 X 10(power4)

Step-by-step explanation:

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Your company estimates that it takes you 20 minutes less each day to complete your filing tasks
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Multiply the number of days by the amount of time you save each week.
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phenytoin comes from the pharmacy as an IV solution of 1000mg/250ml. a loading dose of 700 mg has been ordered. how many millime
Vedmedyk [2.9K]

We can write the following proportion between the milligram and milliliters:

1000\div 250 = 700\div x

Solving for x, we have

x=\dfrac{250\cdot 700}{1000}=175

Intuitively, the original 1000mg/250ml solution tells us that the number of milliliters is one fourth of the number of milligrams.

So, if we want 700mg, we have one fourth of this value for the milliliters:

\dfrac{700}{4}=175

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3 years ago
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