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GenaCL600 [577]
3 years ago
5

Please help pleasee I really need help right now.​

Mathematics
1 answer:
yawa3891 [41]3 years ago
4 0

Answer:

Scale factor: 1.85714285714 or 1.86 (if rounded up)

Step-by-step explanation:

Since the lengths of the triangles are corresponding, you need to count how many lines each triangle measures to.

The small triangle is measured to 7 lines.

The bigger triangle is measured to 13 lines.

13/7 = 1.85714285714 but if rounded up, it's 1.86.

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3 years ago
) e number of viewers ordering a particular pay-per-view program is normally distributed. Past history shows that 33.00% of the
lubasha [3.4K]

Answer:

The mean of the number of people ordering the program is 22,046.5 and the standard deviation is 4,651.16.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Past history shows that 33.00% of the time fewer than 20,000 people order the program

This means that X = 20000 has a pvalue of 0.33. So when X = 20000, Z = -0.44.

Z = \frac{X - \mu}{\sigma}

-0.44 = \frac{20000 - \mu}{\sigma}

20000 - \mu = -0.44\sigma

\mu = 20000 + 0.44\sigma

Only ten percent of the time do more than 28,000 people order the program.

This means that X = 28000 has a pvalue of 1-0.1 = 0.9. So when X = 28000, Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{28000 - \mu}{\sigma}

28000 - \mu = 1.28\sigma

\mu = 28000 - 1.28\sigma

Also

\mu = 20000 + 0.44\sigma

So

20000 + 0.44\sigma = 28000 - 1.28\sigma

1.72\sigma = 8000

\sigma = \frac{8000}{1.72}

\sigma = 4651.16

\mu = 20000 + 0.44\sigma = 20000 + 0.44*4651.16 = 22046.5

The mean of the number of people ordering the program is 22,046.5 and the standard deviation is 4,651.16.

6 0
3 years ago
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