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erastova [34]
3 years ago
6

Please help me<3 <3 <3 <3 <3

Mathematics
1 answer:
Arturiano [62]3 years ago
7 0

Answer: (B) SinA = 4/5

Step-by-step explanation: Sine= O/H or opposite of hypotenuse so in regards to the triangle opposite is 28 and hypotenuse 35 or 28/35 which also equals 4/5

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Grade 7 Math.
marshall27 [118]
Distributive
Communative
Associative
☆is the order.
5 0
3 years ago
Sally is 10 years older than one fifth of her mother’s age. If Sally is 20 years old, how old is her mother?
slamgirl [31]

S = Sally

M = Mother

S = M/5 + 10

20 = M/5 + 10

20 - 10 = M/5

10 = M/5

M = 10 * 5

M = 50

----------------

Her mother is 50 yo

-----------------

50 : 5 + 10 = 20

the answer is good

4 0
3 years ago
When a car travels a distance of d kilometers in time t hours, the average speed for the journey is given by a =4/t km h^-1. fin
zysi [14]

speed=d/t=200X2/5=80km/hr

d=sXt=13X80/4=260km

865/110=173/22hr=173X60/22=173X30/11=467min

4 0
3 years ago
What is the limit ? <br> - does not exist <br> - “infinity”<br> - “-infinity”<br> - 1
Ira Lisetskai [31]

Answer:

Um i think it would be

does not exist

Step-by-step explanation:

sorry if wrong im a little bad at that

7 0
3 years ago
Find the inverse laplace<br><br> F(s)=11s/ s^2-12s+52
lions [1.4K]

Answer:

11e^{6t}\cos 4t+\frac{33}{2}e^{6t}\sin 4t

Step-by-step explanation:

We can write \frac{11s}{s^2-12s+52} as follows:

\frac{11s}{s^2-12s+52}\\=11\left [ \frac{s}{s^2-12s+52} \right ]\\=11\left [ \frac{s}{(s-6)^2+16} \right ]\\=11\left [ \frac{s-6+6}{(s-6)^2+16} \right ]\\=11\left [ \frac{s-6}{(s-6)^2+16} \right ]+\frac{66}{(s-6)^2+16}

To find:

L^{-1}\left [ \frac{11s}{s^2-12s+52 \right ]}\\=L^{-1}\left [ 11\left [ \frac{s-6}{(s-6)^2+16} \right ]+\frac{66}{(s-6)^2+16} \right ]

We will use formulae:

L^{-1}\left \{ \frac{s-a}{(s-a)^2+b^2} \right \}=e^{at}\cos bt\\L^{-1}\left \{ \frac{b}{(s-a)^2+b^2} \right \}=e^{at}\sin bt

we get solution as :

L^{-1}\left [ 11\left [ \frac{s-6}{(s-6)^2+16} \right ]+\frac{66}{(s-6)^2+16} \right ]\\=L^{-1}\left [ 11\left [ \frac{s-6}{(s-6)^2+4^2} \right ]+\frac{66}{4}\left [ \frac{4}{(s-6)^2+4^2} \right ] \right ]\\=11e^{6t}\cos 4t+\frac{33}{2}e^{6t}\sin 4t

5 0
3 years ago
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