A desert that contains plants and animals that have been there a long time is an example of

80cm^3 of oxygen gas diffussed through a porous holebin 50 seconds how long will it take 120cm^3 of nitrogen (iv) oxide to diffu

iogann1982 [59]

Answer:

time for NO₂ to diffuse = 90 s

Explanation:

Data Given:

Amount of O₂ gas transferred = 80 cm³

time of O₂ gas to diffuse = 50s

Amount of NO₂ gas transferred = 120 cm³

time of NO₂ gas to diffuse = ?

Solution:

As we know

rate of diffusion = Amount of gas transferred / time . . . . . . . (1)

we also know that Graham's Law is

rate of diffusion gas A/rate of diffusion gas B = $\sqrt{mB/mA}$ . . . (2)

where

mA = molar mass of gas A

mB = molar mass of gas B

combine both equation 1 and 2

(Amount of gas A transferred / time for gas A) / (Amount of gas B transferred / time for gas B) = $\sqrt{mB/mA}$ . . . . . . . . (3)

we can write equation 3 for oxygen and nitrogen (iv) oxide

(Amount of gas O₂ transferred / time for gas O₂) / (Amount of gas NO₂ transferred / time for gas NO₂) = $\sqrt{m NO₂/mO₂}$ . . . . . . . (4)

molar mass of O₂ = 2 (16) = 32 g/mol

molar mass of NO₂ = 14 + 2(16) = 46 g/mol

Put values in equation equation 4

(80 cm³/50 s) / (120 cm³ / time for NO₂) = $\sqrt{46 g/mol/32 g/mol}$

(1.6 cm³/s)/(120 cm³ / time for NO₂) = $\sqrt{1.44}$

(1.6 cm³/s) / (120 cm³ / time for NO₂) = 1.2

Rearrange the above equation

time for NO₂ = 1.2 /(1.6 cm³/s) x 120 cm³

time for NO₂ = 90 s

So,

time for NO₂ to diffuse = 90 s

6 0

2 years ago

For ethanol, propanol, and n-butanol the boiling points, surface tensions, and viscosities all increase. What is the reason for

vekshin1

Answer:

First choice. The boiling points, surface tension, and viscosities all increase because the strength of dispersion forces increases.

Explanation:

Those properties, boiling points, surface tension, and viscosities are due to the attractive intermolecular forces of the substances.

Ethanol, propanol, and n-butanol (three alcohols) have these chemical formulae:

Ethatnol: CH₃CH₂ OH
Propanol: CH₃ CH₂ CH₂ OH
n-butanol: CH₃CH₂ CH₂ CH₂ OH

So, the molecules of those substances are polar and exhibit all these types of intermolecular bonding forces:

Dipole-dipole interactions: attractive forces between the positive end of one polar molecule and the negative end of another polar molecule;

London dispersion forces: a temporary attractive force that results of temporary assymetry in the electron distribution around the nuclei. This occurs when the electrons in two adjacent atoms occupy positions that cause the atoms form temporary dipoles. These forces exist between any two molecules when they are very, very close to each other (almost touching).

Hydrogen bonding: the strongest intermolecular force. It is a type of dipole-dipole attraction, which arises between an hydrogen atom covalently bonded to a very electronegative atom (in this case oxygen) and the very electronegative atom (oxygen) of a neighboor molecule.

What answer your question is that such hydrogen bonding and dipole-dipole interactions are similar for all the three alcohols, ethanol, propanol, and n-butanol, so they are not responsible for the difference in the mentioned properties, boiling points, surface tension, and viscosities. What is different is the dispersion forces: they increase as the size of the alcohols increase.

As the molecules contain more carbon atoms, lengthen, contain more electrons and, as consequence, the dispersion forces become greater (the magnitude of the temporary dipoles formed increase). This explains the validity of the first statement, that the boiling points, surface tension, and viscosities, all increase because the strength fo the dispersion forces increase.

7 0

2 years ago

PLZ HELP! WILL GIVE BRAINLIEST, 5 STARS, AND A THANKS!!

NISA [10]

Although herbal medicines are less potent in comparison to synthetic drugs in some cases but still these are consider less toxic or having less side effect in contrast to synthetic drugs. The ultimate norm for any medicine (human made or natural) is their non-toxicity, effectiveness, specificity, stability and potency.

7 0

2 years ago

Read 2 more answers

Sports drinks contain sugar, salt, and flavorings dissolved in water . They can be made more or less sweet by adding different a

givi [52]

Answer:

It's a mixture.

Explanation:

Answer from Edgenuity

8 0

2 years ago

Assume that the reaction of aqueous hydrobromic acid solution and potassium hydroxide base undergoes a complete neutralization r

Tamiku [17]

Answer:

a.

$HBr + KOH → KBr + H _{2} O$

b.

$1000 \: ml \: contains \: 0.685 \: moles \\ 55.4 \: ml \: contains \: ( \frac{55.4 \times 0.685}{1000} ) \\ = 0.038 \:moles \\ 1 \: mole \: of \: hydrobromic \: acid \: produces \: 1 \: mole \: of \: water \\ 0.038 \: moles \: produce \: (0.038 \times 1) \\ = 0.038 \: moles \\ 1 \: mole \: of \: water \: weighs \: 18 \: g \\ 0.038 \: moles \: weighs \: (0.038 \times 18) \: g \\ = 0.684 \: g$

c.

0.042 M

d.

1.4

5 0

2 years ago