Answer:
The correct answer to the following question will be "62.9 %".
Explanation:
The given values are:
The aspirin's initial amount = 5.945 g.
and is polluted containing 2,134 g of sodium sulfate.
After extraction we provided 3,739 g of pure aspirin.
Now,
On putting the values in the above formula, we get
⇒ 
⇒ 
Note: percent = %
2 moles of NO3 contains 6 moles of O
Answer: 1.31 moles sulfur
Explanation:
Okay, so this problem involves using molar mass - something we can get from the periodic table. Sulfur has 32.06 grams per mole, or g/mol as sometimes we write it more simply.
How the problem should be set up is something like this:
42.0 grams sulfur times 1 mole sulfur divided by 32.06 grams sulfur, or
(42.0 g) x (1 mole) / (32.06 g)
This should equal 1.310043668122 moles of sulfur.
Taking significant figures into account, we would round the answer to 1.31 moles of sulfur.
