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babunello [35]
3 years ago
7

A soccer ball has a mass of about

Mathematics
2 answers:
dimulka [17.4K]3 years ago
8 0

Answer:

609

Step-by-step explanation:

425+184=609

So the answer is 609

nordsb [41]3 years ago
5 0

Answer:

609g

Step-by-step explanation:

425+184=609

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What is 25 more than n in an algebraic expression
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25 + n
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If a and b are real numbers, what property of real numbers is illustrated by the equation below? 4a + 4b = 4(a + b)
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D. Distributed Property of Multiplication over Addition. Happy Thanksgiving. Hope this helps.

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Solve the equation for all real solutions in the simplest form. -5z^2-3z-11=-6z^2
horsena [70]

Answer:

-3z-11=11z^2

Step-by-step explanation:

3 0
1 year ago
2/3 - 4/9x + 1 = 2 7/9<br><br> By the way, those are fractions and mixed numbers<br><br> Solve x
sukhopar [10]
X=-5/2

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8 0
2 years ago
Read 2 more answers
The table below shows all outcomes for rolling 2 dice. The bold numbers 1 through 6 show the possible results for each die. All
Leokris [45]

Part I:

1. If you have to circle each outcome in the table that at least 1 die is a 4, then you have to circle row corresponding to the number 4 and column corresponding to the number 4.

2. If you have to cross out each outcome where the sum of the dice is greater than 5, then you have to cross out all not bold numbers 6, 7, 8, 9, 10, 11 and 12 in the table.

Part II:

Here you can see 36 possible outcomes.

1. The probability that at least 1 die is a 4 is:

Pr(A)=\dfrac{11}{36} - (favorable outcomes are 4+1=5, 4+2=6, 4+3=7, 4+4=8, 4+5=9, 4+6=10, 1+4=5, 2+4=6, 3+4=7, 5+4=9, 6+4=10).

2. The probability that the sum of the dice is greater than 5 is:

Pr(B)=\dfrac{26}{36}=\dfrac{13}{18}.

3. The probability that at least 1 die is a 4 and that the sum of the dice is greater than 5 is

Pr(A\cap B)=\dfrac{9}{36}=\dfrac{1}{4}.

4. The probability that at least 1 die is a 4 or that the sum of the dice is greater than 5 is:

Pr(A\cup B)=\dfrac{28}{36}=\dfrac{7}{9}.

4 0
3 years ago
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