Answer:
1. The balanced equation:
Zn + 2HCl —> ZnCl₂ + H₂
The coefficients are: 1, 2, 1, 1
2. 2.34 moles of HCl
Explanation:
1. The balanced equation
__Zn + __HCl —> __ZnCl₂ + __H₂
There are 2 atoms of H on the right side and 1 atom on the left side
It can be balance by writing 2 before HCl as shown below:
Zn + 2HCl —> ZnCl₂ + H₂
Now the equation is balanced.
The coefficients are: 1, 2, 1, 1
2. Determination of the number of mole of HCl that reacted.
NOTE: 1 mole of H₂ = 22.4 L at STP.
Zn + 2HCl —> ZnCl₂ + H₂
From the balanced equation above,
2 moles of HCl reacted to produce 1 mole (i.e 22.4 L) of H₂.
Finally, we shall determine the number of mole of HCl needed to produce 26.22 L of H₂. This can be obtained as follow:
From the balanced equation above,
2 moles of HCl reacted to produce 22.4 L of H₂.
Therefore, Xmol of HCl will react to produce 26.22 L of H₂ i.e
Xmol of HCl = (2 × 26.22)/22.4
Xmol of HCl = 2.34 moles
Thus, 2.34 moles of HCl is needed for the reaction.
