The Colorado river slowly eroding the land away, until what it is now.
The percentage composition of the alloy : 19.35% Zn, 80.65%Ag
<h3>Further explanation</h3>
Given
2.55 gram of an alloy
170 cc (170 ml=0.17 L) of Hydrogen gas(H₂)
Ar Zn = 65. H=1
Required
The percentage composition
Solution
Silver remained unsolved⇒no reaction
Hydrogen gas from reaction of Zn
Zn+2HCl⇒ZnCl₂ + H₂
mol H₂ at STP (STP⇒1 mol = 22.4 L) :
From equation, mol ratio Zn : H₂ = 1 : 1, so mol H₂ = 0.00759
Mass Zn :
Mass Silver :
Percent composition :
By using the formula, mass = density x volume, we
calculate mass in grams
20.0 mL CH₃COOH x (1.05 g / mL) = 21.0
g CH₃COOH
To find the moles, molar mass of CH₃COOH = 60.05g/mol<span>
21.0 g </span>CH₃COOH x (1 mole CH₃COOH / 60.05 g CH₃COOH)
= 0.350 moles CH₃COOH
To find molarity,<span>
[</span>CH₃COOH] = moles CH₃COOH / L of solution = 0.350 /
1.40 = 0.250 M CH₃COOH<span>
When </span>CH₃COOH is dissolved in water, it produces
small and equal amounts of H₃O⁺+ and C₂H₃O₂⁻.
<span>
Molarity , </span>CH₃COOH<span> + H</span>₂O <==> H₃O⁺ + C₂H₃O₂⁻
<span>
<span>Initial 0.250 0 0 </span>
Change -x x x
Equilibrium 0.250-x x x
K</span>ₐ = [H₃O⁺][C₂H₃O₂⁻] / [HC₂H₃O₂] = (x)(x) /
(0.250-x) = 1.8 x 10⁻⁵
<span>Since K</span>ₐ is relatively small, we can neglect the -x
term after 0.250 to simplify
<span>x</span>² / 0.250 = 1.8 x 10⁻⁵
x² = 4.5 x 10⁻⁶
<span>
x = 2.1 x 10</span>⁻³<span> = [H</span>₃O⁺]
pH = -log [H₃O⁺] = -log (2.1 x 10⁻³) = 2.68
74.02% is the percent by mass
Copper oxide reacts with hydrochloric acid to produce copper chloride and water.
So the basic equation that illustrates this reaction is:
CuO + HCl ......> CuCl2 + H2O
Now, we need to balance this equation:
the number of copper and oxygen moles are balanced.
For each of hydrogen and chlorine, we have one mole as a reactant and two moles as product.
Therefore, to balance this, we will add an extra mole of HCl in the reactants.
Based on this, the final balanced equation would be:
CuO + 2HCl ................> CuCl2 + H2O
