Answer:
C. how the size of a magnet affects the strength of its magnetic pull on objects.
Explanation:
"Magnetic force" is <em>inversely proportional to distance squared. </em>This is also related to the size of a magnet. The bigger the size, the bigger the domain it occupies and the stronger the magnetic field. However, this is not often the case and it largely depends on the types of magnets.
In the situation above, Jazelle wanted to determine how her five different-sized magnet affect the strength of their magnetic pull on the paper clips. In order to do this, she tried to<em> measure the distance</em>. The<em> closer the distance</em>, the <em>higher the magnetic field</em> and the stronger the strength. The farther the distance, the<em> lower the magnetic field</em> and the <em>weaker the strength.</em>
So, this explains the answer.
Yes, recrystallization from water would be a viable technique of purification if crude acetanilide contained sugar and charcoal. Due to their physical insolubility, charcoal found in crude acetanilide and water will form a heterogeneous combination. Charcoal will separate during crystallization because it is insoluble in water. Sugar and the unreconstituted crude acetanilide make up the remaining portion of the combination. Crude acetanilide will crystallize in this combination and separate from the sugar and water solution. Filtration will be used to capture the crude acetanilide that has solidified. Sugar and water make a soluble solution, thus they are kept separate. This is how the charcoal and sugar combination is purified and its constituent parts are separated from crude acetanilide using the recrystallization process from water.
Answer:
Explanation:
Each iron atom has a mass of about 9 x 1023 grams. Even a small grain of iron has an incredible number of atoms in. it--about 1 x 1018 atoms in one grain. ...
Hey there !
<span>Convert Joule to KJ :
</span>
1 j ---------------- 0.001 kj
53.69 j ----------- Kj
Kj = 53.69 * 0.001
=> 0.05369 Kj
T = ΔH / <span>ΔS
T = 49.09 / 0.05369
T = 914.32ºC</span>
Answer:
The change in internal energy is - 1.19 kJ
Explanation:
<u>Step 1:</u> Data given
Heat released = 3.5 kJ
Volume calorimeter = 0.200 L
Heat release results in a 7.32 °C
Temperature rise for the next experiment = 2.49 °C
<u>Step 2:</u> Calculate Ccalorimeter
Qcal = ccal * ΔT ⇒ 3.50 kJ = Ccal *7.32 °C
Ccal = 3.50 kJ /7.32 °C = 0.478 kJ/°C
<u>Step 3:</u> Calculate energy released
Qcal = 0.478 kJ/°C *2.49 °C = 1.19 kJ
<u>Step 4:</u> Calculate change in internal energy
ΔU = Q + W W = 0 (no expansion)
Qreac = -Qcal = - 1.19 kJ
ΔU = - 1.19 kJ
The change in internal energy is - 1.19 kJ
