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arsen [322]
3 years ago
6

Any method of determining whether an event or object is older or younger than others

Chemistry
2 answers:
anyanavicka [17]3 years ago
7 0

I believe its relative dating.

Inga [223]3 years ago
6 0
The answer is relative dating, btw

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Which of these is a chemical property of iron?
denpristay [2]
Iron becomes rusted especially in damp air but never in a dry air,  this is one of the many unique characteristics of iron. Iron is also ductile and malleable. It is found in the seventh group of the periodic table. It has four different and unique crystalline forms and completely dissolves in dilute acids. The two chemical compounds that can be found or made from iron are the bivalent iron also known as ferrous and the trivalent iron or known as ferric compounds.
7 0
3 years ago
Read 2 more answers
CO2+2H2O=H3O^++HCO3^-
bekas [8.4K]

<u>Answer:</u>

<em>Bronsted Lowry Theory</em>

<em>CO_2 is the acid </em>

<em>H_2 O is the base </em>

<em>H_3 O^+ is the conjugate acid and </em>

<em>HCO_3^- is the conjugate base</em>

<u>Explanation:</u>

Bronsted Lowry Theory:

An acid is a substance that can donate one or more protons

A base is a substance which can accept one or more protons

Hydrogen atom which is neutral (No Charge) contains 1 positive proton, 1 negative electron and 0 neutral neutron.  

Thus Hydrogen atom has no Charge and it is neutral.

When an hydrogen atom loses an electron, Hydrogen ion is formed, which will contain 1 positive proton and 0 negative electron and 0 neutral neutron.

Thus Hydrogen ion has a positive charge.  

Hydrogen ion is also called as a proton since it has only 1 proton in it.

Hydrogen ion in water that is,  

H^++H_2O\Rightarrow H_3O^+

H_3O^+ is called as Hydronium ion.

Acid loses H+ (proton) to form conjugate Base

Base gains H+ (proton) to form conjugate Acid

For example  

Let us consider the example given in the question

CO_2+2H_2 O>H_3 O^+   +HCO_3^- can be written as (removed 1 H_2 O from both the sides )

CO_2+H_2 O>H^++HCO_3^- or  

CO_2+H_2 O  > H_2 CO_3 reversing the equation  

H_2 CO_3+H_2 O>H_3 O^+  +HCO_3^-

H_2 CO_3 is the acid which donates H^+ to form HCO_3^-

H_2 O is the base which gains H^+ to form H_3 O^+

HCO_3^- is the conjugate base and H_3 O^+ is the conjugate acid

So

CO_2 is the acid

H_2 O is the base

H_3 O^+ is the conjugate acid and

HCO_3^- is the conjugate base

(Answer)  

5 0
3 years ago
Plan an investigation using solid and liquid water to show that thermal energy is not the same as temperature.
algol [13]

The investigation using solid and liquid water to show that thermal energy is not the same as temperature is:

  • Place a glass of water and a lake and both should be at the same temperature, find out if do they have the same amount of total thermal energy.

<h3>What is the response to the experiment above?</h3>

The response is No, because the lake is known to have a lot more particles than the glass of water and so they will not have the same  thermal energy.

Note that the temperature is seen as the an average and thermal energy is seen to be the total. A glass of water can be able to have the same temperature as what we call Lake Superior, but the lake has a lot of thermal energy due to the fact that the lake has a lot of water molecules.

So the investigation using solid and liquid water to show that thermal energy is not the same as temperature is Place a glass of water and a lake and both should be at the same temperature, find out if do they have the same amount of total thermal energy.

Learn more about thermal energy from

brainly.com/question/19666326

#SPJ1

4 0
1 year ago
How many atoms are in .800 g of Ca
Goshia [24]
The answer for this question is 0.8
8 0
4 years ago
Read 2 more answers
How do I solve the following word problem: The half-life of Phosphorus - 32 is 14.3 days. It is used to study a plant's use of f
BaLLatris [955]

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

We have the following equation representing the half-life decay:

A=A_o\times2^{(-\frac{t}{t_{half}})_{}_{}}

A is the resulting amount after t time

Ao is the initial amount = 50 mg

t= Elapsed time

t half is the half-life of the substance = 14.3 days

We replace the know values into the equation to have an exponential decay function for a 50mg sample

A=\text{ 50 }\times2^{\frac{-t}{14.3}}

That would be the answer for a)

To know the P-32 remaining after 84 days we have to replace this value in the equation:

\begin{gathered} A=\text{ 50 }\times2^{\frac{-84}{14.3}} \\ A=0.85\text{ mg} \end{gathered}

So, after 84 days the P-32 remaining will be 0.85 mg

4 0
1 year ago
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