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Anton [14]
4 years ago
8

A sample of baking soda, naHCO3, always contains 27.37% by mass of sodium, 1.20% of hydrogen, 14.30% of carbon, and 57.14% of ox

ygen.
Which law do these data illustrate? State the law.
Chemistry
1 answer:
Dvinal [7]4 years ago
4 0

Answer: Law of definite proportion.

Explanation: Law of definite proportion states that any chemical compound consists of elements in a fixed ratio by their masses. This law is also known as Proust's Law.

We are given a chemical compound NaHCO_3

Assuming that the total mass of 1 mole of NaHCO_3 = 100 grams

where

Mass of Sodium = 27.37 grams

Mass of Hydrogen =  1.20 grams

Mass of Carbon = 14.30 grams

Mass of Oxygen = 57.14 grams

To Calculate the ratio of all the elements, we divide each of the masses by the lowest mass.

\text{Mass ratio of Sodium}=\frac{27.37}{1.20}=22.80\approx 23

\text{Mass ratio of Hydrogen}=\frac{1.20}{1.20}=1

\text{Mass ratio of Carbon}=\frac{14.30}{1.20}=11.91\approx 12

\text{Mass ratio of Oxygen}=\frac{57.14}{1.20}=47.61\approx 48

Mass ratio of elements in NaHCO_3=Sodium:Hydrogen:Carbon:Oxygen

Na : H : C : O = 23 : 1 : 12 : 48

For every NaHCO_3 compound, this mass ratio will always be constant.

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Answer: A

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How many atoms are in 0.909 moles of silver?
BabaBlast [244]

Answer:

5.47 x 10^23 atoms in Ag (sliver)

Explanation:

0.909 mol of Ag x 6.02 x 10^23 atoms of Ag/ 1 mol of Ag

8 0
3 years ago
How much silver can be produced from 125g of Ag2S
rosijanka [135]

Answer:

108.9g of Silver can be produced from 125g of Ag2S

Explanation:

The compound Ag2S shows that two atoms of Silver Ag, combined with an atom of Sulphur S to form Ag2S. We can as well say the combination ration of Silver to Sulphur is 2:1

•Now we need to calculate the molecular weight of this compound by summing up the molar masses of each element in the compound.

•Molar mass of Silver Ag= 107.9g/mol

•Molar mass of Sulphur S= 32g/mol

•Molecular weight of Ag2S= (2×107.9g/mol) + 32g/mol

•Molecular weight of Ag2S= 215.8g/mol + 32g/mol= 247.8g/mol

•From our calculations, we know that 215.8g/mol of Ag is present in 247.8g/mol of Ag2S

If 247.8g Ag2S produced 215.8g Ag

125g Ag2S will produce xg Ag

cross multiplying we have

xg= 215.8g × 125g / 247.8g

xg= 26975g/247.8

xg= 108.85g

Therefore, 108.9g of Silver can be produced from 125g of Ag2S

3 0
3 years ago
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You wish to calculate the mass of hydrogen gas that can be prepared from 4.93 g of srh2 and 4.14 g of h2o.
Ivenika [448]
The maximum amount of hydrogen gas that can be prepared is if all the hydrogen from both compounds is released.

The hydrogen in 4.94 g of SrH2 is calculated from the mass ratios between Sr and H

1) H2 in SrH2

Sr atomic mass = 87.62 g/mol

H2 molar mass = 2.02 g/mol

Mass of 1 mol of SrH2 = 87.62 g / mol + 2.02 g/mol = 89.64 g/mol

Ratio of H2 to SrH2 = 2.02 g H2 / 89.64 g SrH2

Proportion: 2.02 g H2 / 89.64 gSrH2 = x / 4.93 g SrH2

=> x = 4.93 g SrH2 * 2.02 g H2 / 89.64 g SrH2 = 0.111 g H2

2) H2 in H2O

2.02 g H2 / 18.02 g H2O * 4.14 g H2O = 0.464 g H2

3) Total mass of hydrogen = 0.111 g + 0.464 g = 0.575 g

Answer: 0.575 g
7 0
3 years ago
How many atoms are there in each of the following
oee [108]
<h3>Answer:</h3><h3>a) 9.033 × 10²³ particles</h3><h3>b) 4.068 × 10²⁴ particles</h3><h3>c) 1.51 × 10²³ particles</h3>

Explanation:

For us to answer these questions, we have to know two formulas:

  1. Number of particles = moles × Avogadro's Number
  2. Moles = Mass ÷ Molar Mass

Therefore:

a) particles of Na = 1.50 mol × (6.022 × 10²³) particles/mol

                            = 9.033 × 10²³ particles

b) particles of Pb = 6.755 mol × (6.022 × 10²³) particles/mol

                            = 4.068 × 10²⁴ particles

c) particles of Si

             = (7.02 g ÷ 28.085 g/mol) × (6.022 × 10²³) particles/mol

             = 1.51 × 10²³ particles

                           

4 0
2 years ago
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