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Anton [14]
4 years ago
8

A sample of baking soda, naHCO3, always contains 27.37% by mass of sodium, 1.20% of hydrogen, 14.30% of carbon, and 57.14% of ox

ygen.
Which law do these data illustrate? State the law.
Chemistry
1 answer:
Dvinal [7]4 years ago
4 0

Answer: Law of definite proportion.

Explanation: Law of definite proportion states that any chemical compound consists of elements in a fixed ratio by their masses. This law is also known as Proust's Law.

We are given a chemical compound NaHCO_3

Assuming that the total mass of 1 mole of NaHCO_3 = 100 grams

where

Mass of Sodium = 27.37 grams

Mass of Hydrogen =  1.20 grams

Mass of Carbon = 14.30 grams

Mass of Oxygen = 57.14 grams

To Calculate the ratio of all the elements, we divide each of the masses by the lowest mass.

\text{Mass ratio of Sodium}=\frac{27.37}{1.20}=22.80\approx 23

\text{Mass ratio of Hydrogen}=\frac{1.20}{1.20}=1

\text{Mass ratio of Carbon}=\frac{14.30}{1.20}=11.91\approx 12

\text{Mass ratio of Oxygen}=\frac{57.14}{1.20}=47.61\approx 48

Mass ratio of elements in NaHCO_3=Sodium:Hydrogen:Carbon:Oxygen

Na : H : C : O = 23 : 1 : 12 : 48

For every NaHCO_3 compound, this mass ratio will always be constant.

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Part 1. A chemist reacted 12.0 liters of F2 gas with NaCl in the laboratory to form Cl2 gas and NaF. Use the ideal gas law equat
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The mass of NaCl needed for the reaction is 91.61 g

We'll begin by calculating the number of mole of F₂ that reacted.

  • Volume (V) = 12 L
  • Temperature (T) = 280 K
  • Pressure (P) = 1.5 atm
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Number of mole (n) =?

PV = nRT

1.5 × 12 = n × 0.0821 × 280

18 = n × 22.988

Divide both side by 22.988

n = 18 / 22.988

n = 0.783 mole

Next, we shall determine the mole of NaCl needed for the reaction.

F₂ + 2NaCl —> Cl₂ + 2NaF

From the balanced equation above,

1 mole of F₂ reacted with 2 moles of NaCl.

Therefore,

0.783 mole F₂ will react with = 0.783 × 2 = 1.566 moles of NaCl.

Finally, we shall determine the mass of 1.566 moles of NaCl.

  • Mole = 1.566 moles
  • Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
  • Mass of NaCl =?

Mass = mole × molar mass

Mass of NaCl = 1.566 × 58.5

Mass of NaCl = 91.61 g

Therefore, the mass of NaCl needed for the reaction is 91.61 g

Learn more about stiochoimetry: brainly.com/question/25830314

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