Solve for t. h(t) = -16t^2 + 150t +70

Alex73 [517]

H 1 : H 2 = 4 : 10
H 1 = 2/5 H 2
and also for the base: L 1 = 2/5 L 2 and W 1 = 2/5 L 2
A 1 = 2 L 1 x W 1 + 2 L 1 x H 1 + 2 W 1 x H 1
A 2 = 2 L 2 x W 2 + 2 L 2 x H 2 + 2 W 2 x H 2
A 1 / A 2 = 4/25 *( 2 L 2 x W 2 + 2 L 2 x H 2 + 2 W 2 H 2 ) /
/ ( 2 L 2 x W 2 + 2 L 2 x H 2 + 2 W 2 x H 2 ) =
= 4/5
A 1 : A 2 = 4 : 25
Answer: B ) 4 : 25

3 0

2 years ago

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Jackie runs and dances for a total of 55 minutes every day. She dances for 25 minutes longer than she runs.

AlladinOne [14]

9514 1404 393

Answer:

A: x + y = 55; y - x = 25

B: 15 minutes running

C: no

Step-by-step explanation:

The two equations relate to the total number of minutes, and to the difference specified in the problem statement.

x + y = 55 . . . . . . total time is 55 minutes

y = x + 25 . . . . . . dances 25 minutes longer

__

We can substitute for y in the first equation to find the value of x, the time spent running.

x + (x +25) = 55

2x = 30 . . . . subtract 25

x = 15 . . . . . . divide by 2

Jackie spends 15 minutes running each day.

__

The value of y from is found using the second equation:

y = x +25 = 15 +25 = 40

Jackie will not spend 45 minutes dancing if she meets the requirements on times.

5 0

2 years ago

You randomly choose one shirt from the shelves. Find the probability of the event.

sweet [91]

 The probability of choosing the red shirt is 1/10.

Hope this will help u...

5 0

2 years ago

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: Use The TI Calculator To Answer The Question. Find The Probability That A Z-score Will Be Between 0.7 And 1.4. A) 0.242 O B) 0

ZanzabumX [31]

Answer:

$P(0.7$

And we can find this probability with the following difference:

$P(0.7$

We can use the following commands on the ti 84

2nd>VARS>DISTR

And then we look for normalcdf and we input this:

normalcdf(0.7,1.4,0,1)

The other possible code would be:

normalcdf(-1000,1,4,0,1)-normalcdf(-1000,0.7,0,1)

And we got:

$P(0.7$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

For this case we want to find this probability:

$P(0.7$

And we can find this probability with the following difference:

$P(0.7$

We can use the following commands on the ti 84

2nd>VARS>DISTR

And then we look for normalcdf and we input this:

normalcdf(0.7,1.4,0,1)

The other possible code would be:

normalcdf(-1000,1,4,0,1)-normalcdf(-1000,0.7,0,1)

And we got: