Answer:
Option 5. 1 and 3
Solution:
The only forces acting on the tennis ball after it has left contact with the racquet and the instant before it touches the ground are the force of gravity in the downward direction and the force by the air exerted on the ball.
The ball after it left follows the path of trajectory and as it moves forward in the horizontal direction the force of the air acts on it.
In the whole projectile motion of the ball, the acceleration due to gravity acts on the ball thus the force of gravity acts on the ball in the downward direction before it hits the ground.
Answer:
WHat do you mean by that
Explanation:
I dont get what you re asking
The formula for resonant frequency is:

Given information:

Plug in the given values to find one value of capacitance:

Plug in the given values to find the other value of capacitance:

This gives a range of 2.429 nF to 26.45 nF.
With significant figures taken into account, the range of capacitance is 2.43 nF to 30 nF.