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d1i1m1o1n [39]
3 years ago
11

What is the approximate range of wavelengths for visible light?

Physics
1 answer:
Korvikt [17]3 years ago
7 0
We can answer the question by looking at the spectrum of the visible light, for example in this figure:
https://en.wikipedia.org/wiki/Light#/media/File:EM_spectrum.svg

We see from the figure that the lowest part of the spectrum (violet) corresponds approximately to a wavelength of 380 nm, while the highest part of the spectrum (red light) corresponds approximately to a wavelength of 750 nm.
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For the hypothetical reaction A → B, calculate the average rate of disappearance of A if the initial concentration of A is 0.91
marishachu [46]

Answer:

The right answer is 8.9 x 10^-3 M/min

Explanation:

           A → B

-d [A]/dt  = K [A]

ΔA/Δt     = - (C2 -C1)/t2 - t1

               = - (0.11 - 0.91)/90

               = 8.9 x 10^-3 M/min

7 0
3 years ago
A boy rides a bike 56 meters. It takes him 8 seconds. What is his speed?
lilavasa [31]

Answer:

7 meters per second or 7 m/s

8 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST IF CORRECT!
Norma-Jean [14]

Answer:

10000N

Explanation:

Given parameters:

Mass of the car  = 1000kg

Acceleration = 3m/s²

g  = 10m/s²

Unknown:

Weight of the car  = ?

Solution:

To solve this problem we must understand that weight is the vertical gravitational force that acts on a body.

 Weight  = mass x acceleration due to gravity

So;

    Weight  = 1000 x 10  = 10000N

5 0
3 years ago
What is meant by the motion of a force​
Vlad [161]

Answer:

Force is classified as a push or a pull

Explanation:

5 0
2 years ago
A swimmer bounces straight up from a diving board and falls feet first into a pool. She starts with a velocity of 4.00 m/s, and
Svetlanka [38]

Answer:

a = 1.152s

b = 0.817 m

c = 7.29m/s

Explanation: let the following

From the first equation of linear motion

V = u+at..........1

parameters be represented as :

t = Time taken

v = Final velocity

a = Acceleration due to gravity = 9.8m/s²

u = Initial velocity = 4 m/s

s = Displacement

V = 0

Substitute the values into equation 1

0 = 4-9.8(t)

-4 = -9.8t

t = 4/9.8

t = 0.408s

From : s = ut+1/2at^2.........2

S = 4×0.408+0.5(-9.8)×0.408^2

S= 1.632-4.9(0.166)

S = 1.632-0.815

S = 0.817m

Her highest height above the board is 0.817 m

Total height she would fall is 0.817+1.90 = 2.717 m

From equation 2

s = ut+1/2at^2

2.717 m = 0t+0.5(9.8)t^2

2.717 m = 0+4.9t^2

2.717 m = 4.9t^2

2.717/4.9 = t^2

0.554 =t^2

t =√0.554

t = 0.744s

Hence, her feet were in the air for 0.744+0.408seconds

= 1.152s

Also recall from equation 1

V= u+at

V = 0+9.8(0.744)

V = 7.29m/s

Hence, the velocity when she hits the water is 7.29m/s

Finally,

a = 1.152s

b = 0.817 m

c = 7.29m/s

4 0
2 years ago
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