Answer: a) C decreases; b) Q stays the same; c) E is the same
d) ΔV increase
Explanation: In order to explain this problem we have to consider the following:
C=εoA/d where A and d are the area and the separation of the plates, respectively.
Increasing d, produces a decrease of C.
Q remain constant becasuse the plates are charges and the wire are isoloted each other.
We also know that ΔV=E*d where E is electric field between the plates.
And E= Q/εo*A ( a constant between the plates)
As we can see from above, ΔV depends directely of the d so if d increase ΔV also increase. To do that we have to do work on the system.
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Net force is the total of all forces acting in the object.
Answer:
A) 62.37 x 10^(6) N
B) 59.86°
Explanation:
A) The magnitude of the force F1 due to the 0.062T magnetic field is;
F1 = |qo|(v)(Bx) Sin 90°
F1 = 1.50 x 10^(5)C x 5.8 x 10³m/s x 0.062T = 53.94 x 10^(6) N
Also, the magnitude of the force F2 due to the 0.036T magnetic field is;
F2 = |qo|(v)(By) Sin 90°
F2 = 1.50 x 10^(5)C x 5.8 x 10³m/s x 0.036T = 31.32 x 10^(6) N
Now, using Fleming's right hand rule, we will discover that the net force makes an angle with the x-axis. Let's call the angle θ. Since the forces will be at right angles to each other, then using Pythagoras theorem will get the resultant met force.
Thus;
F =√((F1)² + (F2)²) = √((53.94 x 10^(6))² + (31.32 x 10^(6))²)
= 62.37 x 10^(6) N
B) Since the forces are at right angles to each other, they are opposite and adjacent and since we know that tangent = opp/adj;
tan θ = F1/F2
tan θ = (53.94 x 10^(6)) / 31.32 x 10^(6) = 1.7222
Thus,θ = tan^(-1) 1.7222
θ = 59.86°
Answer:
velocity = distance / time
distance = speed * time
Distance= 7*3 = 21
V = 21/3
V = 7
Explanation: