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3 years ago

How do linear and exponential functions compare over time?

Mathematics

1 answer:

Murljashka [212]3 years ago

8 0

Answer:

Exponential Functions

In linear functions, rate of change is constant: as x goes up, y will go up a consistent amount. In exponential functions, the rate of change increases by a consistent multiplier—it will never be the same, but there will be a pattern.

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What is -4 3/10 - 8 3/10

nadya68 [22]

Answer:

-12 3/5

Step-by-step explanation:

-4 3/10 - 8 3/10

The signs are the same so we add and then take the sign

4 3/10 + 8 3/10

Add the whole numbers

4+8 = 12

Add the fractions

3/10 + 3/10 = 6/10

Simplify the fraction

6/10 = 3/5

Put them together

12 3/5

Add the sign

-12 3/5

4 0

3 years ago

Read 2 more answers

What is the 28th term of the arithmetic sequence with a 1 = 4 and d= -2

Amiraneli [1.4K]

Answer:

Step-by-step explanation:

tn = a + (n-1)*d

t28 = 4 + (27)*-2 27 because 27 = 28 - 1

t28 = 4 + - 54

t28 = 4 - 54

t28 = - 50

4 0

3 years ago

-1/5(x-4)=-2 how do you solve this equation

m_a_m_a [10]

Multiple both sides by 5/1 and get

-1/1 • (x-4) = -10/1

divide the numbers and get

-1 • (x-4) = -10

remove the parentheses

- x-4 = 10

move the constant to the right

-x = -10-4

calculate

-x = -14

change the signs

x= 14

8 0

3 years ago

Does anyone know the answer to this ??

xenn [34]

Answer:

The answer is C. 14.5 miles

4 0

3 years ago

What is the partial fraction decomposition of StartFraction 8 x + 19 Over (x + 8) (x minus 1) EndFraction? StartFraction 3 Over

hoa [83]

The partial fraction decomposition is $\frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}$

<h3>How to determine the decomposition?</h3>

The fraction is given as:

$\frac{8x + 19}{(x + 8)(x - 1)}$

Split the fraction as follows:

$\frac{8x + 19}{(x + 8)(x - 1)} = \frac{A}{x + 8} + \frac{B}{x - 1}$

Take the LCM

$\frac{8x + 19}{(x + 8)(x - 1)} = \frac{Ax -A + Bx + 8B}{(x + 8)(x -1)}$

Cancel the common factors

8x + 19 = Ax - A + Bx + 8B

By comparison, we have:

Ax + Bx = 8x

-A + 8B = 19

This gives

A + B = 8

-A + 8B = 19

Add both equations

9B = 27

Divide by 9

B = 3

Substitute B = 3 in A + B = 8

A + 3 = 8

Solve for A

A = 5

So, we have:

$\frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}$

Hence, the partial fraction decomposition is $\frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}$

Read more about partial fraction at:

brainly.com/question/12783868

#SPJ1

6 0

2 years ago