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Alex Ar [27]
3 years ago
8

When a potassium ion (K+) moves from the soil into the vacuole of a cell on the surface of a root, it must pass through several

cellular structures. Which of the following correctly describes the order in which these structures will be encountered by the ion? When a potassium ion (K+) moves from the soil into the vacuole of a cell on the surface of a root, it must pass through several cellular structures. Which of the following correctly describes the order in which these structures will be encountered by the ion? primary cell wall → plasma membrane → cytoplasm → secondary cell wall → vacuole plasma membrane → primary cell wall → cytoplasm → vacuole secondary cell wall → plasma membrane → primary cell wall → cytoplasm → vacuole primary cell wall → plasma membrane → lysosome → cytoplasm → vacuole primary cell wall → plasma membrane → cytoplasm → vacuole
Chemistry
1 answer:
insens350 [35]3 years ago
4 0
<h3><u>Answer;</u></h3>

C) primary cell wall → plasma membrane → cytoplasm → vacuole

<h3><u>Explanation;</u></h3>
  • The cell wall is the protective outer layer of a plant cell, that gives the cell strength and structure, and also filters molecules that pass in and out of the cell.
  • Cell membrane acts as a semi-permeable barrier separating the inside of the cell from the outside of the cell. The membrane allows regulation of what enters/exits the cell and how quickly.
  • Cytoplasm is the jelly-like fluid that fills a cell. It is responsible for giving a cell its shape and also helps to fill out the cell and keeps organelles in their place.
  • Vacuoles are membrane-bound sacs within the cytoplasm of a cell that function in several different ways. They functional in providing structural support, as well as serving functions such as storage, waste disposal, protection, and growth.
  • <u>Potassium ion from the extracellular environment will move to the cell vacuole via the cell wall, the cell membrane and then via the cytoplasm to the vacuole.</u>
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Alja [10]

Answer:

439.7nm

Explanation:

Energy of a quantum can be calculated using below formula

E=hv...........eqn(1)

But v=λ/ c .........eqn(2)

If we substitute eqn(2) into eqn(1) we have

E= hc/(λ)

Where E= energy

h= Plank's constant= 6.62607004 × 10-34 m2 kg / s

c= speed of light

c= 2.998 × 10^8 m/s

λ= wavelength= ?

But the energy was given in Kj , it must be converted to Kj/ photon for unit consistency.

Energy E= 272 kJ/mol × 1mol/6.02× 10^23

Energy= 451.83× 10^-24 Kj/ photon

E= hc/(λ)...........eqn(1)

If we make λ subject of the formula

λ= hc/E

Then substitute the values we have

λ= [(6.626 × 10^-34) × (2.998 × 10^8)]/451.83× 10^-24

λ=(0.00043965) × (1Kj/1000J) × (10^9nm/1m)

λ=439.7nm

Hence, the longest wavelength of radiation with enough energy to break carbon-sulfur bonds is 439.7nm

4 0
2 years ago
CO2 <br><br> element <br><br><br> number x Atomic mass =total mass
MaRussiya [10]

Answer:

Number= 6

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Explanation:

4 0
3 years ago
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Virty [35]

Answer:

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D=26, E=30, F =Fe

4 0
3 years ago
When nitrogen dioxide (NO2) from car exhaust combines with water in the air, it forms nitric acid (HNO3), which causes acid rain
yKpoI14uk [10]

<u>Answer:</u>

<u>For a:</u> The number of molecules of nitrogen dioxide is 4.52\times 10^{23}

<u>For b:</u> The mass of nitric acid formed is 54.81 grams

<u>For c:</u> The mass of nitric acid formed is 206 grams

<u>Explanation:</u>

The given chemical reaction follows:

3NO_2(g)+H_2O(l)\rightarrow 2HNO_3(aq.)+NO(g)

  • <u>For a:</u>

By Stoichiometry of the reaction:

1 mole of water reacts with 3 moles of nitrogen dioxide

So, 0.250 moles of water will react with \frac{3}{1}\times 0.250=0.75mol of nitrogen dioxide

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of molecules.

So, 0.75 moles of nitrogen dioxide will contain 0.75\times 6.022\times 10^{23}=4.52\times 10^{23} number of molecules

Hence, the number of molecules of nitrogen dioxide is 4.52\times 10^{23}

  • <u>For b:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of nitrogen dioxide = 60.0 g

Molar mass of nitrogen dioxide = 46 g/mol

Putting values in equation 1, we get:

\text{Moles of nitrogen dioxide}=\frac{60.0g}{46g/mol}=1.304mol

By Stoichiometry of the reaction:

3 moles of nitrogen dioxide produces 2 mole of nitric acid

So, 1.304 moles of nitrogen dioxide will produce = \frac{2}{3}\times 1.304=0.870 moles of nitric acid

Now, calculating the mass of nitric acid from equation 1, we get:

Molar mass of nitric acid = 63 g/mol

Moles of nitric acid = 0.870 moles

Putting values in equation 1, we get:

0.870mol=\frac{\text{Mass of nitric acid}}{63g/mol}\\\\\text{Mass of nitric acid}=(0.870mol\times 63g/mol)=54.81g

Hence, the mass of nitric acid formed is 54.81 grams

  • <u>For c:</u>
  • <u>For nitrogen dioxide:</u>

Given mass of nitrogen dioxide = 225 g

Molar mass of nitrogen dioxide = 46 g/mol

Putting values in equation 1, we get:

\text{Moles of nitrogen dioxide}=\frac{225g}{46g/mol}=4.90mol

  • <u>For water:</u>

Given mass of water = 55.2 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

\text{Moles of water}=\frac{55.2g}{18g/mol}=3.06mol

By Stoichiometry of the reaction:

3 moles of nitrogen dioxide reacts with 1 mole of water

So, 4.90 moles of nitrogen dioxide will react with = \frac{1}{3}\times 4.90=1.63mol of water

As, given amount of water is more than the required amount. So, it is considered as an excess reagent.

Thus, nitrogen dioxide is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

3 mole of nitrogen dioxide produces 2 moles of nitric acid

So, 4.90 moles of nitrogen dioxide will produce \frac{2}{3}\times 4.90=3.27mol of nitric acid

Now, calculating the mass of nitric acid from equation 1, we get:

Molar mass of nitric acid = 63 g/mol

Moles of nitric acid = 3.27 moles

Putting values in equation 1, we get:

3.27mol=\frac{\text{Mass of nitric acid}}{63g/mol}\\\\\text{Mass of nitric acid}=(3.27mol\times 63g/mol)=206g

Hence, the mass of nitric acid formed is 206 grams

7 0
3 years ago
In an experiment, mice were fed glucose (C₆H₁₂O₆) containing a small amount of radioactive carbon. The mice were closely monitor
Luden [163]
<h3>Answer:</h3>

Carbon dioxide

Explanation:

  • Cellular respiration involves a break down of sugars such as glucose to yield energy in the form of ATP and water together with carbon dioxide as byproducts.
  • In this case, when mice are fed with glucose, cellular respiration takes place breaking down glucose to yield energy in the form of ATP, water and carbon dioxide.
  • Therefore, the radioactive carbon in glucose showed up in carbon dioxide, since the carbon in glucose ends up in carbon dioxide.
8 0
3 years ago
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