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Alex Ar [27]
3 years ago
8

When a potassium ion (K+) moves from the soil into the vacuole of a cell on the surface of a root, it must pass through several

cellular structures. Which of the following correctly describes the order in which these structures will be encountered by the ion? When a potassium ion (K+) moves from the soil into the vacuole of a cell on the surface of a root, it must pass through several cellular structures. Which of the following correctly describes the order in which these structures will be encountered by the ion? primary cell wall → plasma membrane → cytoplasm → secondary cell wall → vacuole plasma membrane → primary cell wall → cytoplasm → vacuole secondary cell wall → plasma membrane → primary cell wall → cytoplasm → vacuole primary cell wall → plasma membrane → lysosome → cytoplasm → vacuole primary cell wall → plasma membrane → cytoplasm → vacuole
Chemistry
1 answer:
insens350 [35]3 years ago
4 0
<h3><u>Answer;</u></h3>

C) primary cell wall → plasma membrane → cytoplasm → vacuole

<h3><u>Explanation;</u></h3>
  • The cell wall is the protective outer layer of a plant cell, that gives the cell strength and structure, and also filters molecules that pass in and out of the cell.
  • Cell membrane acts as a semi-permeable barrier separating the inside of the cell from the outside of the cell. The membrane allows regulation of what enters/exits the cell and how quickly.
  • Cytoplasm is the jelly-like fluid that fills a cell. It is responsible for giving a cell its shape and also helps to fill out the cell and keeps organelles in their place.
  • Vacuoles are membrane-bound sacs within the cytoplasm of a cell that function in several different ways. They functional in providing structural support, as well as serving functions such as storage, waste disposal, protection, and growth.
  • <u>Potassium ion from the extracellular environment will move to the cell vacuole via the cell wall, the cell membrane and then via the cytoplasm to the vacuole.</u>
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liq [111]

Answer:

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Explanation:

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6 0
3 years ago
The density of a 3.37M MgCl2 (FW = 95.21) is 1.25 g/mL. Calulate the molality, mass/mass percent, and mass/volume percent. So fa
Dafna1 [17]

Answer : The molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

Solution : Given,

Density of solution = 1.25 g/ml

Molar mass of MgCl_2 (solute) = 95.21 g/mole

3.37 M magnesium chloride means that 3.37 gram of magnesium chloride is present in 1 liter of solution.

The volume of solution = 1 L = 1000 ml

Mass of MgCl_2 (solute) = 3.37 g

First we have to calculate the mass of solute.

\text{Mass of }MgCl_2=\text{Moles of }MgCl_2\times \text{Molar mass of }MgCl_2

\text{Mass of }MgCl_2=3.37mole\times 95.21g/mole=320.86g

Now we have to calculate the mass of solution.

\text{Mass of solution}=\text{Density of solution}\times \text{Volume of solution}=1.25g/ml\times 1000ml=1250g

Mass of solvent = Mass of solution - Mass of solute = 1250 - 320.86 = 929.14 g

Now we have to calculate the molality of the solution.

Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{3.37g\times 1000}{95.21g/mole\times 929.14g}=0.0381mole/Kg

The molality of the solution is, 0.0381 mole/Kg.

Now we have to calculate the mass/mass percent.

\text{Mass by mass percent}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100=\frac{320.86}{1250}\times 100=25.67\%

The mass/mass percent is, 25.67 %

Now we have to calculate the mass/volume percent.

\text{Mass by volume percent}=\frac{\text{Mass of solute}}{\text{Volume of solution}}\times 100=\frac{320.86}{1000}\times 100=32.086\%

The mass/volume percent is, 32.086 %

Therefore, the molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

8 0
3 years ago
Describe four effects that radiation can have on the human body.
Alinara [238K]

Answer:

There are many effects of radiation to the human body. (if you watch the 100, you'll see what happens)

Exposure to very high levels of radiation, such as being close to an atomic blast, can cause acute health effects such as

1. weakness

a/ fatigue,

b/ fainting,

c/ confusion.

2.Bleeding from the nose,

a/ mouth,

b/ gums,

c/ rectum

3. Bruising,

a/ skin burns,

b/ open sores on the skin,

c/ sloughing of skin.

4. Dehydration.

5. Diarrhea, bloody stool.

6. Fever.

7. Hair loss.

8. Inflammation of ex

5 0
3 years ago
Thomas poured 25 mL of 0.60 M HCl into a large bottle. He then added enough water so that the new (diluted) concentration was 0.
Molodets [167]

Answer:

The answer to your question is 150 ml

Explanation:

Data

Volume 1 = 25 ml

Concentration 1 = 0.6 M

Volume 2 = ?

Concentration 2 = 0.1 M

Formula

            Volume 1 x Concentration 1 = Volume 2 x Concentration 2

Solve for Volume 2

             Volume 2 = (Volume 1 x Concentration 1)/Concentration 2

Substitution

             Volume 2 = (25 x 0.6) / 0.1

Simplification

            Volume 2 = 15 / 0.1

Result

            Volume 2 = 150 ml

5 0
3 years ago
1.) A gas occupies 3.5L at 2.5 atm pressure. What is the volume at 10 atm pressure?
romanna [79]

Answer:

.875

Explanation:

Use Boyle's Law and rearrange formula.

- Hope this helps! Please let me know if you need further explanation.

5 0
3 years ago
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