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Anna35 [415]
2 years ago
8

Pleasee help ASAP I’m begging u plssss

Mathematics
1 answer:
Colt1911 [192]2 years ago
8 0
B, y=mx+b
b will always be the y intercept while is the slope
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HELP!<br> Find the Area of the triangle
Zigmanuir [339]

Answer:

A ≈ 65.8 m²

Step-by-step explanation:

Given 2 sides and the angle between them then the area (A) is

A = \frac{1}{2} bc sinA

   = 0.5 × 19.9 × 10.7 × sin38.17°

   ≈ 65.8 m² ( to 1 dec. place )

6 0
2 years ago
Two pools are being drained. To start, the first pool had 3850 liters of water and the second pool had 4370 liters of water. Wat
SashulF [63]

Answer:

(a)

Amount of water in the first pool (in liters) = 3850 liters - 33 liters per minute * x minutes

Amount of water in the second pool (in liters) = 4370 liters - 43 liters per minute * x minutes

(b)

3850 liters - 33 liters per minute * x minutes= 4370 liters - 43 liters per minute * x minutes

Step-by-step explanation:

(a) With x being the minutes after which you want to calculate the amount of water in the pool, to calculate this amount of water you must subtract the water drained from the initial amount of water that the pool contains.

Knowing that, for example, the water from the first pool drains at a rate of 33 liters per minute, then after x minutes, the total water drained will be 33 liters per minute * x minutes. Then:

<u><em>Amount of water in the first pool (in liters) = 3850 liters - 33 liters per minute * x minutes</em></u>

Reasoning in the same way:

<u><em>Amount of water in the second pool (in liters) = 4370 liters - 43 liters per minute * x minutes</em></u>

(b)  Now want to know when the two pools would have the same amount of water.  If they have the same amount of water then you can express:

Amount of water in the first pool = Amount of water in the second pool

Replacing the expressions found in (a):

<u><em>3850 liters - 33 liters per minute * x minutes= 4370 liters - 43 liters per minute * x minutes</em></u>

5 0
3 years ago
3) show that the two lines with the given slopes are parallel, perpendicular neither. My₁ = 3/4 M₂ = 12/16 . solve it by showing
Jet001 [13]

Parallel lines have equal slope so

  • M1-M2=0

Lets check

  • M1=3/4
  • M2=12/16=3/4

Now

  • M1-M2
  • 3/4-3/4
  • 0

Lines are parallel

8 0
2 years ago
Read 2 more answers
How do you solve this? cosθ-tanθcosθ=0
laila [671]
First, lets note that tan(\theta)\cdot cos(\theta)=sin(\theta). This leads us with the following problem:

cos(\theta)-sin(\theta)=0

Lets add sin on both sides, and we get:

cos(\theta)=sin(\theta)

Now if we divide with sin on both sides we get:

\frac{cos(\theta)}{sin(\theta)}=1

Now we can remember how cot is defined, it is (cos/sin). So we have:

cot(\theta)=1

Now take the inverse of cot and we get:
\theta=cot^{-1}(1)=\pi\cdot n+ \frac{\pi}{4} , \quad n\in \mathbb{Z}

In general we have cot^{-1}(1)=\frac{\pi}{4}, the reason we have to add pi times n, is because it is a function that has multiple answers, see the picture:

4 0
3 years ago
Which ordered pair is the reflection of (5,-8) across the x axis and the y axis?
Lerok [7]
The ordered pair would be (-5,8)
3 0
3 years ago
Read 2 more answers
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