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ludmilkaskok [199]
3 years ago
14

A string with a mass of 0.034 kg has a length of 4.80 m. If the tension in the string is 100.00 N and a sinusoidal wave with an

amplitude of 2.40 cm is induced on the string, what must the frequency (in Hz) be for an average power of 200.00 W

Physics
1 answer:
GaryK [48]3 years ago
4 0

Explanation:

Below is an attachment containing the solution.

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17. A volleyball weighs about 300 grams.
atroni [7]

Answer:

PE = 44.1 J

Explanation:

Ok, to have the specific data, the first thing we must do is convert from grams to kilograms. Since mass must always be in kilograms (kg)

We have:

  • 1 kilograms = 1000 grams.

We convert it using a rule of 3, replacing, simplifying units and solving:

  • \boxed{\bold{x=\frac{gr*1\ kg}{1000\ gr}=\frac{300\ gr*1\ kg}{1000\ gr}=\frac{300\ kg}{1000}=\boxed{\bold{0.3\ kg}}}}

==================================================================

Earth's gravity is known to be 9.8 m/s², so we have:

Data:

  • m = 0.3 kg
  • g = 9.8 m/s²
  • h = 15 m
  • PE = ?

Use formula of potencial energy:

  • \boxed{\bold{PE=m*g*h}}

Replace and solve:

  • \boxed{\bold{PE=0.3\ kg*9.8\frac{m}{s^{2}}*15\ m}}
  • \boxed{\boxed{\bold{PE=44.1\ J}}}

Since the decimal number, that is, the number after the comma is less than 5, it cannot be rounded, then we have this result.

The potential energy of the volleyball is <u>44.1 Joules.</u>

Greetings.

8 0
3 years ago
Helppppp pleaseee :(
Elza [17]

1) push down on the end of the lever, and 2) 3/4 of the way from the fulcrum

7 0
3 years ago
Helppppp pleaseeeee!!!!!!!
Lorico [155]
The first one is Water
The second one is Juice
The third one Vinegar
The fourth one is Milk
The last one may be Shampoo


3 0
3 years ago
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Schach [20]
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4 0
2 years ago
The speed of sound in air is 10 times faster than the speed of a wave on a certain string. The density of the string is 0.002kg/
nata0808 [166]

Answer:

The tension on the string is 2.353 N.

Explanation:

Given;

the speed of sound in air, v₀ = 343 m/s

then, the speed of sound on the string, v = 343 / 10 = 34.3 m/s

mass per unit length, m/l = μ = 0.002 kg/m

The speed of sound on the string is given as;

v = \sqrt{\frac{T}{\mu} } \\\\v^2 = \frac{T}{\mu} \\\\T = v^2 \mu

where;

T is the tension on the string

T = (34.3)²(0.002)

T = 2.353 N

Therefore, the tension on the string is 2.353 N.

3 0
3 years ago
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