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ludmilkaskok [199]

3 years ago

14

A string with a mass of 0.034 kg has a length of 4.80 m. If the tension in the string is 100.00 N and a sinusoidal wave with an

amplitude of 2.40 cm is induced on the string, what must the frequency (in Hz) be for an average power of 200.00 W

1 answer:

GaryK [48]3 years ago

4 0

Explanation:

Below is an attachment containing the solution.

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How do the densities of the jovian and terrestrial planets compare?

timofeeve [1]

Hello

The jovian density is $1.33~g/cm^3$ , while the density of terrestrial planets is much higher. For instance, the earth's density is $5.51~g/cm^3$ . The reason of this difference is in the different chemical composition: while jupiter is made of gas (mainly hydrogen), with lower density, while the terrestrial planets are made of solid and liquid, with compounds of higher density.

5 0

3 years ago

The weight y of a fiddler crab is directly proportional to the 1.25 power of the weight x of its claws. A crab with a body weigh

frez [133]

Answer:

The weight of body is 1.3040 gram.

Explanation:

Given that,

The weight y of a fiddler crab is directly proportional to the 1.25 power of the weight x of its claws.

Suppose a crab with a body weight of 1.8 gram has claws weighing 1.1 gram.

Estimate the weight of a fiddler crab with claws weighing 0.85 gram.

Determine the weight of crab body

We need to calculate the value of proportional constant

$y\propto x^{1.25}$

$y=kx^{1.25}$

$k=\dfrac{y}{x^{1.25}}$

Put the value into the formula

$k=\dfrac{1.8}{1.1^{1.25}}$

$k=1.5978$

We need to calculate the crab weight

$y=kx^{1.25}$

Here, x = 0.85 g

Put the value into the formula

$y=1.5978\times(0.85)^{1.25}$

$y=1.3040\ gram$

Hence, The weight of body is 1.3040 gram.

7 0

4 years ago

Metal sphere 1 has a positive charge of 7.00 nc . metal sphere 2, which is twice the diameter of sphere 1, is initially uncharge

MariettaO [177]

Answer:

2.33 nC, 4.67 nC

Explanation:

when the two spheres are connected through the wire, the total charge (Q=7.00 nC) re-distribute to the two sphere in such a way that the two spheres are at same potential:

$V_1 = V_2$ (1)

Keeping in mind the relationship between charge, voltage and capacitance:

$C=\frac{Q}{V}$

we can re-write (1) as

$\frac{Q_1}{C_1}=\frac{Q_2}{C_2}$ (2)

where:

Q1, Q2 are the charges on the two spheres

C1, C2 are the capacitances of the two spheres

The capacitance of a sphere is given by

$C=4 \pi \epsilon_0 R$

where R is the radius of the sphere. Substituting this into (2), we find

$\frac{Q_1}{4 \pi \epsilon_0 R_1}=\frac{Q_2}{4 \pi \epsilon_0 R_2}$ (3)

we also know that sphere 2 has twice the diameter of sphere 1, so the radius of sphere 2 is twice the radius of sphere 1:

$R_2 = 2R_1$

So the eq.(3) becomes

$\frac{Q_1}{4 \pi \epsilon_0 R_1}=\frac{Q_2}{4 \pi \epsilon_0 2R_1}$

And re-arranging it we find:

$Q_2 = 2Q_1$

And since we know that the total charge is

$Q_1 + Q_2 = 7.00 nC$

we find

$Q_1 = 2.33 nC\\Q_2 = 4.67 nC$

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4 years ago

Fossils reveal which of the following about a species or organism

pentagon [3]

The appearance of the organism and its structures, because the fossils are basically worn out parts of the organism. IT IS basically the organism.

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4 years ago

An egg suspended above the ground has 93.1 J of gravitational potential energy. The egg is then dropped and falls to the ground.

Marina86 [1]

93.1 J of kinetic energy

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3 years ago