Isn’t it 1 / 1 ?or something like that is positive for sure
Answer:
part 1= "72=(2w)+(w-15)"
part 2= "29"
I'm not sure if they want "w = abc"
I used that equation to solve part 2
Hope this helps you, I've been where you are
Answer:
<h2>3 + 4(n - 1)</h2>
Step-by-step explanation:
let r be the common differenc of the sequence
Term 12 - Term 7 = (12 - 7)r
then
47 - 27 = 5r
then
20 = 5r
then
r = 4
term 7 = term 1 + (7 - 1)r
then
27 = term 1 + 6r = term 1 + 24
then
Term1 = 27 - 24 = 3
<em><u>therefore </u></em>
the standard explicit formula of the sequence is :
term 1 + (n - 1)r = 3 + 4(n - 1)
Answer:
<h3>
9, 11, 13, 15</h3>
Step-by-step explanation:
{k - some integer}
2k+1 - the first odd integer (the least)
5(2k+1) - five times the least
5(2k+1)+3 -<u> three more than five times the least</u>
2k+1+2 = 2k+3 - the odd integer consecutive to 2k+1
2k+3+2 = 2k+5 - the next odd consecutive integer (third)
2k+5+2 = 2k+7 - the last odd consecutive integer (fourth)
2k+1+2k+3+2k+5+2k+7 - <u>the sum of four odd consecutive integers</u>
2k+1 + 2k+3 + 2k+5 + 2k+7 = 5(2k+1) + 3
8k + 16 = 10k + 5 + 3
- 10k -10k
-2k + 16 = 8
-16 - 16
-2k = -8
÷(-2) ÷(-2)
k = 4
2k+1 = 2•4+1 = 9
2k+3 = 2•4+3 = 11
2k+5 = 2•4+5 = 13
2k+7 = 2•4+7 = 15
Check: 9+11+13+15 = 48; 48-3 = 45; 45:5 = 9 = 2k+1
So to find the width (w)
26=2(7+w). W=6
