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Mariulka [41]
3 years ago
10

I need help please pleasssssssssssse​

Mathematics
2 answers:
NeX [460]3 years ago
5 0
I think it’s 37 for number 4
Dahasolnce [82]3 years ago
4 0

Answer:

Uhhhhh

21 maybe

I think is 23

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Which table represents a linear function?
ELEN [110]

Answer:

2=y 5=x

Step-by-step explanation:

its the answer of your question

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3 years ago
Francis teaches the piano. He charges each student an enrollment fee of $100 plus $15 per hour of piano lessons. The average cos
Sergeeva-Olga [200]

Answer:

The first one should be right. Since the teacher is charging $15 per hour of the piano lesson then it can't be any of the answers of $100h. The answer can't be C, the third one, since you're adding the enrollment fee to the cost of every piano lesson it would be wrong to subtract the $100. Hope that helps!

Step-by-step explanation:

The answer will the answer on the top $25=$100+$15h over h

6 0
3 years ago
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PLEASE HELP 10 POINTS
Sidana [21]

Answer:

8.1 gallons

Step-by-step explanation:

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5 0
4 years ago
Use algebraic rules of equations to predict the solution to the system of equations. Include all of your work for full credit.
bezimeni [28]
Use substitution
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7 0
3 years ago
What is the slop intercept form of a line that passes threw (4,-4) and (8, -10)
BigorU [14]

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

We have two points through which the line passes, so we can find the slope:

(x_ {1}, y_ {1}) :( 4, -4)\\(x_ {2}, y_ {2}) :( 8, -10)\\m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {-10 - (- 4)} {8-4} = \frac {-10+ 4} {4} = \frac {-6} {4} = - \frac {3} {2}

Thus, the equation is of the form:

y = - \frac {3} {2} x + b

We substitute one of the points and find "b":

-4 = - \frac {3} {2} (4) + b\\-4 = - \frac {12} {2} + b\\-4 + 6 = b\\b = 2

Finally, the equation is of the form:

y = - \frac {3} {2} +2

ANswer:

y = - \frac {3} {2} +2

4 0
3 years ago
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