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Ivenika [448]
3 years ago
15

Can someone please solve this. I got 81

Mathematics
1 answer:
aksik [14]3 years ago
6 0
To solve:

Find the volume of the pyramid first:
Base=9
Height=3
Volume=1/2(3)(9)=13.5

Then the volume of the rectangular prism:
Base=9
Height=16
Volume=144

Add the volumes of the two shapes together:
144+13.5=157.5

Answer: 157.5 ft^3
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Percent that equals 7/8
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Answer:

.875

Step-by-step explanation:

7 divided by 8 is .875.

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3 years ago
Read 2 more answers
Plz help ASAP, giving brainliest!
lapo4ka [179]
D is the answer you want
5 0
3 years ago
A hiker is climbing down a valley. He stops for a water break 4 times. Between each break, he descends 15 meters. How many meter
Murljashka [212]

The word in the problem that indicates that a negative sign should be used is "descend"

<h3></h3><h3>How many meters did he descend?</h3>

We know that he stops for water breaks four times, and between each water break, he descends 15 meters.

The written equation is:

4*(-15)m = -60m

Why the negative sign is used?

The negative sign is used because the hiker is descending, so its height is decreasing. The word in the problem that indicates that a negative sign should be used is "descend"

If you want to learn more about signs:

brainly.com/question/5870782

#SPJ1

7 0
2 years ago
can somebody please help me on this if you know how to solve it is urgent please don’t waste my answers
forsale [732]

Answer:

  6

Step-by-step explanation:

The angle bisector divides the other segments proportionally. There are many ways the proportion can be written. One is ...

  XN/NY = XA/AY

  XN = NY×XA/AY = 4 × 18/12

  XN = 6

3 0
3 years ago
I do not understand how I find answers on here
Volgvan
All you have to do is write your question and someone will answer. For example, instead of writing "I do not understand how I find answers on here" you would ask something like what is 9*5? Then 2 people will see your question and answer. There are no pre-recorded answers, everything happens live. Hope this helps!
6 0
3 years ago
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