Answer:
1. 39 J; 2. 3.9 % usable; 3. 96.1 % unusable
Step-by-step explanation:
1. Available energy
Energy consumed = 1000 J
Less waste = - 177 J
Less respiration = <u>-784 J
</u>
Total energy lost = <u>-961 J
</u>
Available energy = 39 J
2. Percent of total energy usable
The chipmunk could use only 39 J of the original 1000 J.
% of energy usable = 39 J/1000 J × 100 % = 3.9 %
3. Percent of energy unusable
The chipmunk lost 961 J of the original 1000 J.
% of energy unusable = 961 J/1000 J × 100 % = 96.1 %
Answer:
- Reduced risk of neural tube defects- <u>diet adequate in synthetic form of folate </u>
-
Reduced risk of hypertension and stroke- <u>diet low in sodium and high in potassium </u>
-
Reduced risk of cardiovascular disease- <u>fatty acids from oils present in fish </u>
-
Reduced risk of some types of cancer- <u>diet rich in fiber</u>
Explanation:
As you may already know, the adequate intake of certain nutrients is very beneficial to our body and to improve and maintain our health. That's because these nutrients act in the construction of essential molecules to keep our body functioning in a healthy and adequate way. Among the numerous nutrients necessary for our health, we can mention that the adequate intake of folate has the ability to reduce the creation of possible defects in the neural tube, while a diet rich in potassium can reduce the risks of hypertension, especially if accompanied by a low sodium diet. Following this same reasoning, a diet rich in fiber can reduce the risk of cancer, in addition to promoting good bowel function. Last but not least, a diet rich in fatty acids from fish can reduce cardiovascular disease.
Om said that he had a lot more than a little more money than his wife and I was in the middle of a meeting with the guy that was going through the house and I had to go back and forth with him
Answer: they are mostly single celled organisms and they usually reproduce A-sexually.
Passive transport<span> is a movement of </span>biochemicals<span> and other </span>atomic<span> or </span>molecular<span> substances across </span>cell membranes through <span>concentration gradients</span><span> without need of </span>energy<span> input. Unlike </span>active transport<span>, it does not require an input of cellular energy because it is instead driven by the tendency of the system to grow in </span>entropy<span>. The rate of passive transport depends on the </span>permeability<span> of the cell membrane, which, in turn, depends on the organization and characteristics of the membrane </span>lipids<span> and </span>proteins<span>. The four main kinds of passive transport are simple </span>diffusion<span>, </span>facilitated diffusion<span>, </span>filtration<span>, and </span>osmosis.
