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3 years ago

Which Variable Is Most Important To The Following Problem?

Mathematics

1 answer:

Alekssandra [29.7K]3 years ago

4 0

Answer:

Step-by-step explanation:

this equation can be derived from the question :

95,000 - 250x = 75,000

where x is the equal amount of shares purchased for each client

given the amount of shares that remains after the shares has been purchased, we can determine the amount of shares bought by dividing the difference between 95,000 and 75,000 by 250

the price of each share was not made reference to in the question, thus it is not an important variable

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Twice x, plus 4, is the same as -6.

BARSIC [14]

Start by writing what is said:
2x + 4 = -6
From there just solve for x:

Subtract 4 from both sides
2x + 4 - 4 = -6 - 4
2x = -10

Divide by 2 to get x by itself
2x/2 = -10/2
x = -5

6 0

3 years ago

Read 2 more answers

If you stacked Avogadro's number of pennies one on top of the other on Earth's surface, how far would the stack extend (in kilom

miskamm [114]

Answer:my

The height of the stack will be 9.15×10^20_m

Or 9.15×10^17_Km

Which is 6 billion times more more than the distance to the sun

Or 22.9 million times further than the star Proxima Centauri

Step-by-step explanation:

Given

Avogadro's number = 6.02×10^23 particles

And the thickness of a penny = 1.52_mm

The height of the stack will be

1.52 × 6.02 ×10^23 = 9.15×10^23_mm 9.15×10^20_m

7 0

3 years ago

28.47 % of 637.38 cm

kykrilka [37]

Answer:

181.46 cm

Step-by-step explanation:

28.47 * 637.47 / 100 = 181.46

3 0

3 years ago

Find the mode of the following data Stem: 2,3,4,5 Leaves: 8,1,1,6,0,2,4,3,5

Fittoniya [83]

One 1 because it has occured twice in the question.

7 0

3 years ago

Suppose f⃗ (x,y,z)=⟨x,y,4z⟩f→(x,y,z)=⟨x,y,4z⟩. let w be the solid bounded by the paraboloid z=x2+y 2 z=x2+y2 and the plane z=9.z

Aleonysh [2.5K]

$\mathbf F(x,y,z)=\langle x,y,4z\rangle$

By the divergence theorem, the surface integral taken over $S$ ,

$\displaystyle\iint_S\mathbf F\,\mathrm dS$

is equivalent to the triple integral of the divergence of $\mathbf F$ over $W$ , the space bounded $S$ ,

$\displaystyle\iiint_W(\nabla\cdot\mathbf F)\,\mathrm dV$

We have

$\nabla\cdot\mathbf F=\dfrac{\partial x}{\partial x}+\dfrac{\partial y}{\partial y}+\dfrac{\partial(4z)}{\partial z}=1+1+4=6$

The latter integral is then given by

$\displaystyle6\iiint_W\mathrm dV=6\int_{|x|\le3}\int_{|y|\le3}\int_{x^2+y^2\le z\le9}\mathrm dz\,\mathrm dy\,\mathrm dx=648$

5 0

3 years ago