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slavikrds [6]
3 years ago
5

The house Trevor's family lives in has 6 66 people (including Trevor) and 3 33 bathrooms. In the past month, each person showere

d for an average of 480 480480 minutes and used an average 72 7272 liters of shower water (over the entire month). Water costs 0.20 0.200, point, 20 dollars per liter. How much did Trevor's family pay per minute on shower water?
Mathematics
1 answer:
yKpoI14uk [10]3 years ago
4 0

Answer:

The amount Trevor's family pay per minute on shower water is $0.005.

Step-by-step explanation:

The cost of water is,

Cost = $0.20/liter

Amount of water used over the entire month:

Amount of water used = 72 liters

Compute the total water cost as follows:

Total water cost = Amount of water used × Cost

                           = 72 × 0.20

                           = $14.4/liter

The average number of minutes each person showered is:

Average number of minutes = 480 minutes.

The number of people in Trevor's house:

N = 6

Compute the total amount of time the 6 person showered as follows:

Total amount of time = Average number of minutes × N

                                   = 480 × 6

                                   = 2880 minutes

Compute the pay per minute on shower water as follows:

Pay per minute on water = Total water cost ÷ Total amount of time

                                          = $14.4 ÷ 2880

                                          = $0.005

Thus, the amount Trevor's family pay per minute on shower water is $0.005.

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james' daily wage was $5 more than Davis's. Although James worked 3 days less than David, they earned $180 each. Find the number
zalisa [80]

Answer: 9 days

Step-by-step explanation:

Let x represent James' daily wage

James' daily wage was $5 more than Davis's. It means that Davis's daily wage will be $(x-5)

Let y represent number of days that James worked. James worked 3 days less than David. It means that the number of days that Davis worked would be (y + 3) days

they earned $180 each. Total amount of money earned by either of of them is the product of wage and the number of days worked.

Since James earned $180, then

180 = xy - - - - - - - - 1

Since Davis also earned $180, then

180 = (x - 5)(y + 3)

xy +3x -5y -15 = 180 - - - - - - - - 2

Substituting xy = 180 into equation 2

It becomes

180 + 3x - 5y -15 = 180

3x - 5y = 180 - 180 + 15

3x - 5y = 15 - - - - - - -3

From equation 1, x = 180/y

Substituting x = 180/y into equation 3, it becomes

3 × 180/y - 5y = 15

540 - 5y^2 = 15y

5y^2 + 15y -540 = 0

Dividing through by 5

y^2 + 3y -108 = 0

y^2 + 12y - 9y -108 = 0

y(y + 12) - 9(y + 12) = 0

y + 12 = 0 or y - 9 = 0

y = -12 or y = 9

Since the number of days cannot be negative, then,

Number of days that James worked will be 9 days

8 0
3 years ago
In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hir
Ede4ka [16]

Answer:

Explained below.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}= p

The standard deviation of this sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

(a)

The sample selected is of size <em>n</em> = 450 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204

So, the sampling distribution of sample proportion is \hat p\sim N(0.75,0.0204^{2}).

(b)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

P(p-0.04

                                          =P(-1.96

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.

(c)

The sample selected is of size <em>n</em> = 200 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306

So, the sampling distribution of sample proportion is \hat p\sim N(0.75,0.0306^{2}).

(d)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

P(p-0.04

                                          =P(-1.31

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.

(e)

The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.

And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.

So, there is a gain in precision on increasing the sample size.

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kay was walking along the bridge above the river. She accidentally lost her grip on her camera when she was trying to get it out
zhenek [66]
5 seconds 
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6 0
3 years ago
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Need help with this math problem
grandymaker [24]

Answer:

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Step-by-step explanation:

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now you do 180-(45+48) = 87

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3 years ago
When there are 20 sheep, each sheep has 100 square yards of grazing area . How many yards are available for each sheep when ther
ZanzabumX [31]

Answer:

80 square yards

Step-by-step explanation:

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3 0
4 years ago
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