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2 years ago

How many subatomic particles are in the NUCLEUS of a neutral atom of Beryllium?

Chemistry

2 answers:

Georgia [21]2 years ago

7 0

Uh according to my calculations it’s gotta be one of those answer choices.

ser-zykov [4K]2 years ago

6 0

Answer:

Explanation:

There are 4 protons, 5 neutrons, and 4 electrons. This is a neutral beryllium atom.

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Using P1V1/T1 = P2V2/T2, 1 being the conditions initially and 2 being the secondary conditions…. always make sure you convert you units first , L=695.8262L

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2 years ago

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2 years ago

How many atoms are in 10g of Al

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Answer:

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Explanation:

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3 years ago

True or False: Acids react with some metals to produce hydrogen gas

Sedaia [141]

Acids react with most metals to form a salt and hydrogen gas. ... For example, zinc metal reacts with hydrochloric acid producing zinc chloride and hydrogen gas. \[\ce{Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)}\] Bases react with certain metals like zinc or aluminum for example to also produce hydrogen gas.

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3 years ago

In the laboratory you dissolve 19.1 g of ammonium fluoride in a volumetric flask and add water to a total volume of 375 . mL. Wh

11111nata11111 [884]

Answer:

1.376 M

Explanation:

The following data were obtained from the question:

Mass of ammonium fluoride (NH₄F) = 19.1 g

Volume of solution = 375 mL

Molarity of ammonium fluoride (NH₄F) =?

Next, we shall convert 375 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

375 mL = 375 mL × 1 L / 1000 mL

375 mL = 0.375 L

Next, we shall determine the number of mole in 19.1 g of ammonium fluoride (NH₄F). This can be obtained as follow:

Mass of NH₄F = 19.1 g

Molar mass of NH₄F = 14 + (4×1) + 19

= 14 + 4 + 19

Molar mass of NH₄F = 37 g/mol

Mole of NH₄F =?

Mole = mass /Molar mass

Mole of NH₄F = 19.1 / 37

Mole of NH₄F = 0.516 mole

Finally, we shall determine the molarity of the solution. This can be obtained as follow:

Volume of solution = 0.375 L

Mole of NH₄F = 0.516 mole

Molarity of NH₄F =?

Molarity = mole /Volume

Molarity of NH₄F = 0.516 / 0.375

Molarity of NH₄F = 1.376 M

Therefore, the molarity of the ammonium fluoride (NH₄F) is 1.376 M

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2 years ago