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vichka [17]
2 years ago
15

The combustion of hydrogen gas releases 286 kJ per mol of hydrogen. If 13.0 L of hydrogen at STP was burned to produce electrici

ty, how long would it power a 100-watt (W) light bulb
Chemistry
1 answer:
photoshop1234 [79]2 years ago
5 0

Combustion of hydrogen produces electricity:

It would power a 100-watt (W) light bulb in 27.66 min.

Calculation:

At STP conditions, we know that 1 mole of any gas is contained in 22.4L.

So let's make the operation:

The volume of one mole of gas at STP is 22.4 L

Then, 13.0 L may be the volume for (13.0) /22.4  = 0.58 moles.

The total energy is released = 0.58 x 286 kJ

Total energy = 165.98 kJ

Energy = Power x time

Time = energy / power

where power = 100W = 100 J/s

Therefore, Time = 165.98 kJ/ 100J/s = 1659.8 sec

Time = 1659.8 sec / 60 min = 27.66 min

∴ Time = 27.66 min

Learn more about combustion here,

brainly.com/question/13746752

#SPJ4

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3 0
3 years ago
Which ion formation takes more energy: K+ or Li+?
Dima020 [189]

Answer:

Li⁺

Explanation:

In ion formation, the ionization energy plays a very important role. To form an ion, an atom will lose or gain an electron to become charged.

The higher the ionization energy of an atom, the more the energy required to remove an electron from it to form an ion.

  • Ionization energy is the energy required to remove an electron from an atom.
  • It is the readiness of an atom to lose an electron. The lower the value, the easier it is for an atom to lose an electron and vice versa.

Generally, down the group, ionization energy decreases. Since both potassium and lithium are in group 1, Li will have a higher ionization energy. It will take more energy to form Li⁺ compared to K⁺.

3 0
2 years ago
A 2.0 sample of N2 occupy 50.0L at 15 degrees Celsius and 640mmHg. What volume will the gas occupy at 45 degrees Celsius and 160
inysia [295]

Answer:

220.8L

Explanation:

Given parameters:

Initial volume  = 50L

Initial temperature = 15°C  = 288K

Initial pressure = 640mmHg

Final temperature  = 45°C  = 318K

Final pressure  = 160mmHg

Unknown:

Final volume  = ?

Solution:

Using the combined law;

        \frac{p_{1}v_{1}  }{T_{1} }  = \frac{p_{2}v_{2}  }{T_{2} }  

p,v and T are pressure, volume and Temperature

    \frac{640 x 50}{288}  = \frac{160 x v_{2} }{318}

     160 x 288 x v₂ = 640 x 50 x 318

                         v₂ = 220.8L

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