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vichka [17]
2 years ago
15

The combustion of hydrogen gas releases 286 kJ per mol of hydrogen. If 13.0 L of hydrogen at STP was burned to produce electrici

ty, how long would it power a 100-watt (W) light bulb
Chemistry
1 answer:
photoshop1234 [79]2 years ago
5 0

Combustion of hydrogen produces electricity:

It would power a 100-watt (W) light bulb in 27.66 min.

Calculation:

At STP conditions, we know that 1 mole of any gas is contained in 22.4L.

So let's make the operation:

The volume of one mole of gas at STP is 22.4 L

Then, 13.0 L may be the volume for (13.0) /22.4  = 0.58 moles.

The total energy is released = 0.58 x 286 kJ

Total energy = 165.98 kJ

Energy = Power x time

Time = energy / power

where power = 100W = 100 J/s

Therefore, Time = 165.98 kJ/ 100J/s = 1659.8 sec

Time = 1659.8 sec / 60 min = 27.66 min

∴ Time = 27.66 min

Learn more about combustion here,

brainly.com/question/13746752

#SPJ4

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A scientist collects 0.24 mole of hydrogen gas in a balloon. The temperature of the hydrogen is 35 degrees Celsius, and the pres
slava [35]

Answer:

             5.77 L

Solution:

Data Given:

                Moles  =  n  =  0.24 mol

                Temperature  =  T  =  35 °C + 273  =  308 K

                 Pressure  =  P  =  1.05 atm

                 Volume  =  V  =  ?

Formula Used:

Let's assume that the hydrogen gas in balloon is acting as an Ideal gas, the according to Ideal Gas Equation,

                 P V  =  n R T

where;  R  =  Universal Gas Constant  =  0.082057 atm.L.mol⁻¹.K⁻¹

Solving Equation for V,

                 V  =  n R T / P

Putting Values,

                 V  =  (0.24 mol × 0.082057 atm.L.mol⁻¹.K⁻¹ × 308 K) ÷ 1.05 atm

                 V  = 5.77 L

6 0
4 years ago
Unknown # 21
Nutka1998 [239]
Answer is option B
Addictive and always Agn02
8 0
3 years ago
Which synthetic polymer is made into fibers that do not wear out easily?
Alekssandra [29.7K]
C its Nylon that's the Synthetic polymer that doesnt wear out easily
6 0
3 years ago
Read 2 more answers
What is the mass of of 3.20 X 10^23 particles of Co2?​
vitfil [10]

Answer:

Mass = 23.36 g

Explanation:

Given data:

Number of particles of CO₂ = 3.20 ×10²³

Mass of  CO₂ = ?

Solution:

1 mole contain 6.022×`10²³ particles,

3.20 ×10²³ particles  × 1 mol / 6.022×`10²³ particles

0.531 mol

Mass of CO₂:

Mass = number of moles × molar mass

Molar mass = 44 g/mol

Mass =  0.531 mol× 44 g/mol

Mass = 23.36 g

6 0
3 years ago
In the explosion of a hydrogen-filled balloon, 0.60 g of hydrogen reacted with 4.8 g of oxygen. how many grams of water vapor ar
Kaylis [27]
First write the balanced equation of this reaction:
2H2 + O2 —> 2H2O

mol of H2= 0.60 gH2/2.02 gH2 = 0.297 mol
There are 2 mol of H2 for every 2 mol of H2O so the number of mol of H2 is equal to the number of mol of H2O.
g of H2O = 0.297 mol H2O • 18.02 gH2O = 5.35 g H2O

Do the same thing for O2:
mol of O2 = 4.8 gO2/32.0 gO2 = 0.15 mol of O2
There is 1 mol of O2 for every 2 mol of H2O so multiply 0.15 • 2 to get the number of mol of H2O
g of H2O = 0.30 mol H2O • 18.02 gH2O = 5.41 g H2O

The correct answer is 5.35 g H2O (or 5.4 g if checking significant figures) because O2, in this case, is the limiting reactant of this reaction.
8 0
3 years ago
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