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vichka [17]
2 years ago
15

The combustion of hydrogen gas releases 286 kJ per mol of hydrogen. If 13.0 L of hydrogen at STP was burned to produce electrici

ty, how long would it power a 100-watt (W) light bulb
Chemistry
1 answer:
photoshop1234 [79]2 years ago
5 0

Combustion of hydrogen produces electricity:

It would power a 100-watt (W) light bulb in 27.66 min.

Calculation:

At STP conditions, we know that 1 mole of any gas is contained in 22.4L.

So let's make the operation:

The volume of one mole of gas at STP is 22.4 L

Then, 13.0 L may be the volume for (13.0) /22.4  = 0.58 moles.

The total energy is released = 0.58 x 286 kJ

Total energy = 165.98 kJ

Energy = Power x time

Time = energy / power

where power = 100W = 100 J/s

Therefore, Time = 165.98 kJ/ 100J/s = 1659.8 sec

Time = 1659.8 sec / 60 min = 27.66 min

∴ Time = 27.66 min

Learn more about combustion here,

brainly.com/question/13746752

#SPJ4

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Answer:

A methane molecule is made from one carbon atom and four hydrogen atoms. Carbon has a mass of 12.011 u and hydrogen has a mass of 1.008 u. This means that the mass of one methane molecule is 12.011 u + (4 × 1.008u), or 16.043 u. This means that one mole of methane has a mass of 16.043 grams.

メタン分子は、1つの炭素原子と4つの水素原子から作られています。炭素の質量は12.011uで、水素の質量は1.008uです。これは、1つのメタン分子の質量が12.011 u +(4×1.008u)、つまり16.043uであることを意味します。これは、1モルのメタンの質量が16.043グラムであることを意味します。^>^

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Answer:

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D - We have crude oil located more than 4000 yards below the surface in countries like Brazil

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Explanation:

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