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Alona [7]
3 years ago
10

How moles are in 45.7g of CH3?

Chemistry
1 answer:
miskamm [114]3 years ago
6 0

first find the atomic weight of CH3 which would be

atomic weight: 12.011 (3×1.008) = 36.32 g/mol

then find the moles in the given mass

36.32 ÷ 45.7 = 0.794

I HOPE I'M NOT WRONG I HAVENT DONE CHEM IN SO LONG

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Will a precipitate of magnesium fluoride form when 300. mL of 1.1 × 10 –3 M MgCl 2 are added to 500. mL of 1.2 × 10 –3 M NaF? [K
Tju [1.3M]

Answer:

No precipitate is formed.

Explanation:

Hello,

In this case, given the dissociation reaction of magnesium fluoride:

MgF_2(s)\rightleftharpoons Mg^{2+}+2F^-

And the undergoing chemical reaction:

MgCl_2+2NaF\rightarrow MgF_2+2NaCl

We need to compute the yielded moles of magnesium fluoride, but first we need to identify the limiting reactant for which we compute the available moles of magnesium chloride:

n_{MgCl_2}=0.3L*1.1x10^{-3}mol/L=3.3x10^{-4}molMgCl_2

Next, the moles of magnesium chloride consumed by the sodium fluoride:

n_{MgCl_2}^{consumed}=0.5L*1.2x10^{-3}molNaF/L*\frac{1molCaCl_2}{2molNaF} =3x10^{-4}molMgCl_2

Thus, less moles are consumed by the NaF, for which the moles of formed magnesium fluoride are:

n_{MgF_2}=3x10^{-4}molMgCl_2*\frac{1molMgF_2}{1molMgCl_2}=3x10^{-4}molMgF_2

Next, since the magnesium fluoride to magnesium and fluoride ions is in a 1:1 and 1:2 molar ratio, the concentrations of such ions are:

[Mg^{2+}]=\frac{3x10^{-4}molMg^{+2}}{(0.3+0.5)L} =3.75x10^{-4}M

[F^-]=\frac{2*3x10^{-4}molMg^{+2}}{(0.3+0.5)L} =7.5x10^{-4}M

Thereby, the reaction quotient is:

Q=(3.75x10^{-4})(7.5x10^{-4})^2=2.11x10^{-10}

In such a way, since Q<Ksp we say that the ions tend to be formed, so no precipitate is formed.

Regards.

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. Which information is NOT included in each square of the periodic table in your text? a. atomic number c. melting point b. chem
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Answer:

A: Antibonding molecular orbitals are higher in energy than all of the bonding molecular orbitals.

Explanation:

Molecular  orbital theory describes <u>covalent bonds in terms of molecular orbitals</u>, which  result from interaction of the atomic orbitals of the bonding atoms and are associated  with the entire molecule.

A bonding molecular orbital has lower  energy and greater stability than the atomic orbitals from which it was formed. An  antibonding molecular orbital has higher energy and lower stability than the  atomic orbitals from which it was formed.

Electrons in the antibonding molecular orbital have  higher energy (and less stability) than they would have in the isolated atoms. On the  other hand, electrons in the bonding molecular orbital have less energy (and hence  greater stability) than they would have in the isolated atoms.

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