Pythagorus Theorm
a sqr + b sqr = c sqr
25 sqr + 7 sqr = c sqr
625 + 49 = c sqr
625 + 49 = 674
c = sqr root of 674
c = 25.96 (rounded to 2dp)
When the diagonals of a quadrilateral are perpendicular, the area of that quadrilateral is half the product of their lengths.
.. A = (1/2)*d₁*d₂
Substituting the given information, this becomes
.. 58 in² = (1/2)*(14.5 in)*d₂
.. 2*58/14.5 in = d₂ = 8 in
The length of diagonal BD is 8 in.
Answer:
p = 6; RPQ = 60 degrees
Step-by-step explanation:
Because RPS is 120 degrees and it is bisected by PQ (cut into 2 equal parts), we can determine that both sides are 60 degrees. Set the expression 5p+30 equal to 60 to find the value of p.
5p + 30 = 60
5p = 30
p = 6
So now you have determined that p = 6, and the measure of RPQ is 60 degrees.
Hope this helped!
Answer: The area is 201.06
Answer:
The graph crosses the x-axis 2 times
The solutions are x = -8 & x = 4
Step-by-step explanation:
Qaudratics are in the form 
Where a, b, c are constants
Now, let's arrange this equation in this form:

Where
a = 1
b = 4
c = -32
We need to know the discriminant to know nature of roots. The discriminant is:

If
- D = 0 , we have 2 similar root and there is 2 solutions and that touches the x-axis
- D > 0, we have 2 distinct roots/solutions and both cut the x-axis
- D < 0, we have imaginary roots and it never cuts the x-axis
Let's find value of Discriminant:

Certainly D > 0, so there are 2 distinct roots and cuts the x-axis twice.
We get the roots/solutions by factoring:

Thus,
The graph crosses the x-axis 2 times
The solutions are x = -8 & x = 4