6.55 meters of fencing. Simply subtract 13.45 meters and 9.5 meters from 42.6 meters, and then divide by 3.
Answer:
x=-2 y=3
Step-by-step explanation:
The substitution is basically given to you. Exchange x from the second equation with y-5
Once that is done and you combine the parentheses you get:
2y-10+y=-1
Add 10 on both sides of the equal sign
You get:
3y=9
Divide both sides by 3
You get:
y=3
To check your work you can substitute y in the second equation with 3 and solve it that way to get x=-2 (x equals negative two)
C. Action: Divide both sides by 3.
Answer:
∠EFH = 21°
∠HFG = 62°
∠EFG = 83°
Step-by-step explanation:
The diagram showing the angles has been attached to this response.
From the diagram, it can be deduced that;
Angle EFG = angle EFH + angle HFG
=> ∠EFG = ∠EFH + ∠HFG -------------------(i)
From the question:
∠EFH = (5x + 1)° -------------(ii)
∠HFG = 62° -------------(iii)
∠EFG = (18x + 11)° -------------(iv)
<em>Substitute these values into equation (i) as follows;</em>
(18x + 11) = (5x + 1) + 62
=> 18x + 11 = 5x + 1 + 62
<em>Collect like terms and solve for x</em>
18x - 5x = 1 + 62 - 11
13x = 52
x = 4
Now, to get each measurement, substitute x = 4 into each of equations (ii) - (iv)
∠EFH = (5x + 1)°
∠EFH = (5(4) + 1)°
∠EFH = (20 + 1)°
∠EFH = 21°
∠HFG = 62° [<em>Does not depend on x</em>]
∠EFG = (18x + 11)°
∠EFG = (18(4) + 11)°
∠EFG = (72 + 11)°
∠EFG = 83°
<u>Conclusion:</u>
∠EFH = 21°
∠HFG = 62°
∠EFG = 83°
(The Answer is 0) let’s say x is the Number of Aerobics classes
5x=3x
2x=0
X=0