The function of the area of the square is A(t)=121
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11
⇒x=11t
Area of square=
Area of square={as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
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Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11
⇒x=11t
Area of square=
Area of square={as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
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Answer:
6k+234
Step-by-Step Explanation:
Add 9, 3, 212, 3, and 7. You get 234. You can't change 6k because the variable, so you end up with 6k+234.
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Answer: $150
Step-by-step explanation:
Becky spends 3/5 of her Money and is left with 2/5 of her money.
Hence 2 parts = $60
And 5 parts = $150
Becky has $150 at first.