Answer:
What is the average translational kinetic energy of molecules in an ideal gas at 37°C? The average translational energy of a molecule is given by the equipartition theorem as, E = 3kT 2 where k is the Boltzmann constant and T is the absolute temperature.
Explanation:
The average translational energy of a molecule is given by the equipartition theorem as, E = 3kT 2 where k is the Boltzmann constant and T is the absolute temperature.
Answer:
answer is 10km
Explanation:
use "S =Ut "
S=distance U=velocity t =time
no need to convert time into seconds as the velocity has given in meters per minute
==> The total mass resting on the table is (5 kg + 3 kg) = 8 kg.
==> The total weight of that mass is (8 kg) x (9.8 m/s) = 78.4 newtons
==> The boxes are stacked. So the table doesn't know if the weight on it is coming from one box, 2 boxes, 3 boxes, or 100 boxes in a stack. The table only knows that there is a downward force of 78.4 newtons on it.
==> The table stands in a Physics classroom, and it soaks up everything it hears there. It knows that every action produces an equal and opposite reaction, and that forces always occur in pairs.
Ever since the day it was only a pile of lumber out behind the hardware store in the rain, the table has known that in order to maintain the good reputation of tables all over the world, it must resist the weight of anything placed upon it with an identical upward force. This is the normal thing for all good tables to do, up to the ultimate structural limit of their materials and construction, and it is known as the "normal force".
So the table in your question provides a normal force of 78.4 newtons. (d)
Answer:
The dimension of power is energy divided by the time or ![[ML^2T^-3]](https://tex.z-dn.net/?f=%5BML%5E2T%5E-3%5D)
Explanation:
Power =
We can derive Dimensions of Power from both formula.
Power = Force * Velocity
As,
Force = mass * acceleration
Therefore, Dimensions of
Force = ![[M]*[LT^-2] = [MLT^-2]](https://tex.z-dn.net/?f=%5BM%5D%2A%5BLT%5E-2%5D%20%3D%20%5BMLT%5E-2%5D)
Since,
Velocity = 
Now, Dimension of
Velocity = ![[LT^-1]](https://tex.z-dn.net/?f=%5BLT%5E-1%5D)
We have Both Dimensions,Now we can derive Dimensions Of Power,
Power = Force * Velocity
Power =![[MLT^-2] * [LT^-1]](https://tex.z-dn.net/?f=%5BMLT%5E-2%5D%20%2A%20%5BLT%5E-1%5D)
Power =
