Answer:
Mass = 14.876 g
Explanation:
Given data:
Volume of gold = 0.77 cm³
Mass of gold = ?
Solution:
Density of gold from literature is 19.32 g/cm³
Formula:
d = m/v
d = density
m = mass
v = volume
by putting values,
19.32 g/cm³ = m/ 0.77 cm³
m = 19.32 g/cm³ × 0.77 cm³
m = 14.876 g
Answer:
<u>-16200J</u>
Explanation:
(257J/g)(62.9g)
eliminate the variables
u get 16165.3
go to 3 significant digits
u get 16200
and since it is freezing we are taking out energy so it would be
-16200J
In 1 mole of magnesium there are Avogadro's number of atoms are present.
Avogadro's number = 6.023 x 10²³
1 mole = 6.023 x 10²³ atoms
3.75 moles = 3.75 x 6.023 x 10²³
=2.26 x 10²⁴
So, in 3.75 moles of magnesium there are 2.26 x 10²⁴ atoms of magnesium are present.
Answer:
I can list four. These are the main ones.
Bolling
Filtration
Distillation.
Chlorination
Explanation:
The answer is <span>ReGallium or Indium</span>
