Answer:
5.559*10^(23) atoms
Explanation:
Molar Mass of Al(OH)3 = 78 g/mol
(72g/78g/mol)*(6.022*10^(23)atoms/mol) = 5.559*10^(23) atoms in 72 grams of Al(OH)3
<span>Mn(HPO4)2 - managanese (II) monohydrogen phosphate ion</span>
A gas that occupies 4.31 litres at a pressure of 0.755 atm will have a temperature of 39.58°C. Details about temperature can be found below.
<h3>How to calculate temperature?</h3>
The temperature of a gas can be calculated using the following formula:
PV = nRT
Where;
- P = pressure
- V = volume
- n = number of moles
- R = gas law constant
- T = temperature
0.755 × 4.31 = 1 × 0.0821 × T
3.25 = 0.0821T
T = 3.25 ÷ 0.0821
T = 39.58°C
Therefore, a gas that occupies 4.31 litres at a pressure of 0.755 atm will have a temperature of 39.58°C.
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Answer:
The answer is "2.459".
Explanation:
The cell potential or emf norm = oxidation pot. of anode -oxidation pot. of cathode
When the pot oxidizer is the opposite of a red pot size it's been transformed to either the redox reaction so that anode was its higher oxide pot material that means (AL) so,
![\to emf=1.66-(-0.799) \\\\ \to emf=1.66+0.799) \\\\ \to emf =2.459](https://tex.z-dn.net/?f=%5Cto%20emf%3D1.66-%28-0.799%29%20%5C%5C%5C%5C%20%5Cto%20emf%3D1.66%2B0.799%29%20%5C%5C%5C%5C%20%5Cto%20emf%20%3D2.459)
the answer is temperature