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Free_Kalibri [48]
3 years ago
5

In the covalent compound CH3, the Greek prefix used to represent the anion is Answer here​

Chemistry
1 answer:
Contact [7]3 years ago
3 0

Answer:

Tri.

Explanation:

''Tri'' is the Greek prefix used to represent the CH3 because there are three hydrogen atoms to form the covalent compound so in Greek method ''Tri'' is used for three. In Greek system, there are certain names for prefixes such as ''di'' is used for two, ''tri'' is used for three, ''tetra'' is used for four etc. This method only provides information about the number of atoms that form the covalent compound.

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How many moles are in 4.818 x 1024 chloride ions
erastovalidia [21]

Answer:

<h3>The answer is 8.00 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L}  \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{4.818 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 8.00332225...

We have the final answer as

<h3>8.00 moles</h3>

Hope this helps you

4 0
3 years ago
The picture shows a scientist operating an instrument that measures earthquakes. Identify the TWO terms from the list below that
Liula [17]

Answer:

The answers are A) Seismograph, and B) Primary (P) Waves

Explanation:

A is one because a seismograph measures seismic waves to gauge the intensity of an earthquake, such as B, P Waves, which are the earliest waves, the ones that tell you an earthquake is coming.

Good Luck!

5 0
3 years ago
I'll give 40 pts for this one but pls help me....
Ivenika [448]
3 of them left and i just need points lol sorrrry
3 0
3 years ago
So the relative mass of fluorine in the second compound is one-third that of sf6. what formula expresses one-third the amount of
stealth61 [152]

The formula SF_2 expresses one-third the amount of F.

The F:S ratio in the first compound is 6:1.

We want a compound with one third the amount of F, so F:S = 2:1.

The simplest formula with this ratio is SF_2.

5 0
4 years ago
A 0.130 mole quantity of NiCl 2 is added to a liter of 1.20 M NH 3 solution. What is the concentration of Ni 2 + ions at equilib
rosijanka [135]

This is an incomplete question, here is a complete question.

A 0.130 mole quantity of NiCl₂ is added to a liter of 1.20 M NH₃ solution. What is the concentration of Ni²⁺ ions at equilibrium? Assume the formation constant of Ni(NH₃)₆²⁺ is 5.5 × 10⁸

Answer : The concentration of Ni^{2+} ions at equilibrium is, 4.31\times 10^{-8}

Explanation :  Given,

Moles of NiCl_2 = 0.130 mol

Volume of solution = 1 L

Concentration=\frac{Moles }{Volume}

Concentration of NiCl_2 = Concentration of Ni^{2+} = 0.130 M

Concentration of NH_3 = 1.20 M

K_f=5.5\times 10^8

The equilibrium reaction will be:

                      Ni^{2+}(aq)+6NH_3(aq)\rightarrow [Ni(NH_3)_6]^{2+}

Initial conc.    0.130       1.20                     0

At eqm.             x       [1.20-6(0.130)]      0.130

                                   = 0.42

The expression for equilibrium constant is:

K_f=\frac{[Ni(NH_3)_6^{2+}]}{[Ni^{2+}][NH_3]^6}

Now put all the given values in this expression, we get:

5.5\times 10^8=\frac{(0.130)}{(x)\times (0.42)^6}

x=4.31\times 10^{-8}

Thus, the concentration of Ni^{2+} ions at equilibrium is, 4.31\times 10^{-8}

7 0
4 years ago
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