Answer:
<h3>The answer is 8.00 moles</h3>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula

where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have

We have the final answer as
<h3>8.00 moles</h3>
Hope this helps you
Answer:
The answers are A) Seismograph, and B) Primary (P) Waves
Explanation:
A is one because a seismograph measures seismic waves to gauge the intensity of an earthquake, such as B, P Waves, which are the earliest waves, the ones that tell you an earthquake is coming.
Good Luck!
3 of them left and i just need points lol sorrrry
The formula SF_2 expresses one-third the amount of F.
The F:S ratio in the first compound is 6:1.
We want a compound with one third the amount of F, so F:S = 2:1.
The simplest formula with this ratio is SF_2.
This is an incomplete question, here is a complete question.
A 0.130 mole quantity of NiCl₂ is added to a liter of 1.20 M NH₃ solution. What is the concentration of Ni²⁺ ions at equilibrium? Assume the formation constant of Ni(NH₃)₆²⁺ is 5.5 × 10⁸
Answer : The concentration of
ions at equilibrium is, 
Explanation : Given,
Moles of
= 0.130 mol
Volume of solution = 1 L

Concentration of
= Concentration of
= 0.130 M
Concentration of
= 1.20 M

The equilibrium reaction will be:
![Ni^{2+}(aq)+6NH_3(aq)\rightarrow [Ni(NH_3)_6]^{2+}](https://tex.z-dn.net/?f=Ni%5E%7B2%2B%7D%28aq%29%2B6NH_3%28aq%29%5Crightarrow%20%5BNi%28NH_3%29_6%5D%5E%7B2%2B%7D)
Initial conc. 0.130 1.20 0
At eqm. x [1.20-6(0.130)] 0.130
= 0.42
The expression for equilibrium constant is:
![K_f=\frac{[Ni(NH_3)_6^{2+}]}{[Ni^{2+}][NH_3]^6}](https://tex.z-dn.net/?f=K_f%3D%5Cfrac%7B%5BNi%28NH_3%29_6%5E%7B2%2B%7D%5D%7D%7B%5BNi%5E%7B2%2B%7D%5D%5BNH_3%5D%5E6%7D)
Now put all the given values in this expression, we get:


Thus, the concentration of
ions at equilibrium is, 