Use the following image to answer the question:

Mathematics

2 answers:

Cloud [144]3 years ago

7 0

Answer:

the answer is the state trial.

Step-by-step explanation:

Citrus2011 [14]3 years ago

4 0

Answer:

US Circuit Courts of Appeals

Step-by-step explanation:

The lowest courts are circuit courts. They are the courts of original jurisdiction. The 24 Illinois Circuit Courts can hear almost all cases. The intermediate courts are the appellate courts. There are five appellate districts. The court of last resort is the Supreme Court. The Illinois Supreme Court can hear cases directly from a circuit or an appellate court in the state.

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The price of 3 books is Rs.330 . How many such books can be bought for Rs.550 ?

AysviL [449]

330/3= 110
550/110=5

Answer is 5 books

5 0

3 years ago

Read 2 more answers

Which operation results in a binomial? (3y ^ 6 + 4) (9y ^ 12 - 12y ^ 6 + 16)

AleksAgata [21]

Step-by-step explanation:

Given the expression, $(3y ^ 6 + 4) (9y ^ {12} - 12y ^ 6 + 16)$ , we want to know which sign placed in between the two polynomial will produce a binomial.

Using a plus (+) sign to check:

$= (3y ^ 6 + 4) + (9y ^ {12} - 12y ^ 6 + 16)\\= (3y ^ 6 + 4) + (9y ^ {12} - 12y ^ 6 + 16)\\collect \ like \ terms\\= 9y^{12} +3y^6 - 12y^6 + 16+ 4\\= 9y^{12} - 9y^6 + 20\\$

From the gotten value, it can be seen that the resulting answer produces 3 terms, showing that it results in a trinomial instead of binomial.

Using a plus (-) sign to check:

$= (3y ^ 6 + 4) - (9y ^ {12} - 12y ^ 6 + 16)\\= 3y ^ 6 + 4 - 9y ^ {12} + 12y ^ 6 - 16\\collect \ like \ terms\\= -9y^{12} +3y^6 +12y^6 + 4-16\\= -9y^{12} +15y^6 -12\\$

From the gotten value, it can be seen that the resulting answer produces 3 terms, showing that it results in a trinomial instead of binomial.

<em>Hence none of the operations given results in a binomial</em>

3 0

3 years ago

Evaluate $\dfrac{2\sqrt{72}}{\sqrt{8}+\sqrt{2}}$.

Pavlova-9 [17]

<h3>Answer: 4</h3>

========================================================

Work Shown:

$\frac{2\sqrt{72}}{\sqrt{8}+\sqrt{2}}\\\\\frac{2\sqrt{36*2}}{\sqrt{4*2}+\sqrt{2}}\\\\\frac{2\sqrt{36}*\sqrt{2}}{\sqrt{4}*\sqrt{2}+\sqrt{2}}\\\\\frac{2*6*\sqrt{2}}{2*\sqrt{2}+\sqrt{2}}\\\\\frac{12\sqrt{2}}{2\sqrt{2}+\sqrt{2}}\\\\\frac{12\sqrt{2}}{3\sqrt{2}}\\\\\frac{12}{3}\\\\4$

Note in step 2, I factored each number in the square root to pull out the largest perfect square factor. From there, I used the rule that $\sqrt{A*B} = \sqrt{A}*\sqrt{B}$ to break up the roots.