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bogdanovich [222]
3 years ago
13

Miguel’s family drove 357 miles on their weekend trip. Their car’s average gas mileage was 25.5 miles per gallon. How many gallo

ns of gas did they use? Round your answer to the nearest tenth of a gallon if necessary. 1.4 gallons 14 gallons 21 gallons 41 gallons 91 gallons 140 gallons
Chemistry
2 answers:
ad-work [718]3 years ago
6 0

Answer:

14 gallons

Explanation:

357 divided by 14 = 25.5 and if you check your answer 14 x 25.5 = 357 (i hope this is right)

nikklg [1K]3 years ago
3 0

Answer:

2.7

Explanation:

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The reaction that has been, following the law of conservation of mass has been \rm C_6H_1_2O_6\;+\;6\;O_2\;\rightarrow\;6\;CO_2\;+\;6\;H_2O\;+\;Energy.

The law of conservation has been given in the chemical reaction that there has been no loss or gain of the mass and energy.

The law of conservation has been evident when there has been an equal number of atoms of each element on the product and the reactant side.

<h3 /><h3>Conservation of mass in Cellular respiration</h3>

The following reactions have been identified as:

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Carbon atoms

Reactant = 3

Product = 18

Oxygen atoms

Reactant = 9

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Hydrogen atoms

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The number of atoms is not equal on the product and reactant side, thus not follows the law of conservation of mass.

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Oxygen atoms

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Carbon atoms

Reactant = 6

Product = 6

Oxygen atoms

Reactant = 18

Product = 18

Hydrogen atoms

Reactant = 12

Product = 12

The number of atoms is equal on the product and reactant side, thus follows the law of conservation of mass.

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Reactant = 6

Product = 0

Oxygen atoms

Reactant = 12

Product = 12

Hydrogen atoms

Reactant = 24

Product = 0

The number of atoms is not equal on the product and reactant side, thus not follows the law of conservation of mass.

Thus, the reaction that has been following the law of conservation of mass has been \rm C_6H_1_2O_6\;+\;6\;O_2\;\rightarrow\;6\;CO_2\;+\;6\;H_2O\;+\;Energy.

Learn more about law of conservation, here:

brainly.com/question/2175724

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When the glucose solution described in part A is connected to an unknown solution via a semipermeable membrane, the unknown solu
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<span> B. possibility of mining minerals</span>
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125 cm3 of a solution contains 0.25 moles of the solute. What is the concentration of the solution?
jarptica [38.1K]

Answer:

Explanation:

125 cm3 -> 0.125 L

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