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kkurt [141]
3 years ago
10

A normal distribution has a mean of 85.3 and a standard deviation of 4.85. Find the data value corresponding to the value of z g

iven. (Enter your answer to four decimal places.) z = 0.55
Mathematics
1 answer:
Mazyrski [523]3 years ago
6 0

Answer: 87.9675

Step-by-step explanation:

Formula for z:

z=\dfrac{x-\mu}{\sigma}, where x= data value corresponding to z, \mu = mean, \sigma = standrad deviation.

Given: \mu =85.3, \sigma =4.85, z=0.55

To find : x

0.55=\dfrac{x-85.3}{4.85}\\\\\Rightarrow\ 0.55\times4.85=x-85.3\\\\\Rightarrow\ 2.6675=x-85.3\\\\\Rightarrow\ x=85.3+2.6675\\\\\Rightarrow\ x=87.9675

Hence, The required data value= 87.9675

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Insert parenthesis () to make the following problem true: 3+6-2x4=19
tia_tia [17]

Answer:

3+(6-2)*4=19

Step-by-step explanation:

Due to PEMDAS, it would first be required to do "6-2", which is 4.

Then, the 4 in the parenthesis is multiplied by the 4 on the outside, making 16.

Finally, 3 would be added to 16, making 19.

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Rudik [331]

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X^2 - y^2 = 100
luda_lava [24]

Answer:

20

Step-by-step explanation:

Let's start by rewriting the second equation in terms of "x":

x+y=5

Subtract y from both sides:

x=5-y

Now, substitute "5-y" for "x" in the first equation:

(5-y)^2-y^2=100

Note that:

(a-b)^2=a^2-2ab+b^2

25-10y+y^2-y^2=100

Cancel out like terms:

25-10y=100

Subtract 25 from both sides:

-10y=75

Divide both sides by -10

y=\frac{75}{-10}=\frac{15}{-2}=-\frac{15}{2}

Now, substitute this value back into either of the equations to solve for x.

x+y=5\\x-\frac{15}{2}=5\\

Add 15/2 to both sides:

x=5+\frac{15}{2}\\x=\frac{10}{2}+\frac{15}{2}\\x=\frac{25}{2}

Now, find the difference:

x-y=\frac{25}{2}-(-\frac{15}{2})=\frac{25}{2}+\frac{15}{2}=\frac{40}{2}=20

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2 years ago
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REY [17]
I think that is correct !!
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