P = 2l + 2w
Subtract both sides by 2w
P - 2w = 2l
Divide both sides by 2
(P - 2w) / 2 = l
In our problem,
w = 7 in
P = 42 in
Let's plug our values into the formula above.
(42 in - 2(7 in) / 2 = l
(42 in - 14 in) / 2 = l
28 / 2 = l
14 in = length
This answer would be a cuboid because it has parallel,perpendicular,and diagonal cross sections
Answer:
1. {1/20} 2. {7/36} 3. {1/2} 4. {8/21} 5. {4/15}
6.{1/6} 7.{ 20} 8. {15} 9. {1.2} 10. {1.25}
Step-by-step explanation:
Answer: The three consecutive odd integers are: -15, -13, and -11 .
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Explanation:
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x + (x + 2) + (x + 4) = -39 ;
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in which "x" is one of the integers,
"(x + 2)" is the next consecutive odd integer;
"(x + 4)" is the third consecutive odd integer.
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By solving for "x", we can solve for each of three (3) consecutive odd integers.
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x + (x + 2) + (x + 4) = -39 ;
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1x + 1x + 2 + 1x+ 4 = -39 ;
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3x + 6 = -39 ;
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Subtract "6" from EACH side of the equation:
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3x + 6 − 6 = -39 <span>− 6 ;
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to get: 3x = -45 ;
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Divide EACH side of the equation by "3" ;
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3x / 3 = -45 / 3 ;
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to get: x = -15 ;
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x + 2 = -15 + 2 = -13 ;
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x + 4 = -15 + 4 = -11 .
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Are: -15, -13, and -11 ; Consecutive odd integers? YES!
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Does: -15 + (-13) + (-11) =? = -39 ??
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-15 </span>− 13 <span>− 11 = ? 39 ?? YES!
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Answer: The three consecutive odd integers are: -15, -13, and -11.
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A. 8 pizza pies at 10 pc. per pie = 80 available pieces
B. Let X be the number of children. Number of pieces eaten = 5 per child = 5X.
c. 22 pieces are left over.
D. Combine line A and line C. Total number of pieces eaten = 80 original minus 22 left over. Result 58 pieces were eaten by X children: 58 = 5X.
E. Solve the equation 58 = 5X by dividing both sides by 5.
WHOOPS! Is this a trick question? Solving the above results in the answer that there are 11.6 children at the party. Hmmm. That 0.6 child is a question mark for me.
Looks like someone miscounted the pizza slices. Or omitted some pertinent information. But, I’m sure there is a logical answer.
