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astra-53 [7]
2 years ago
9

A 1430 kg is moving at 25.6 m/s when a force is applied, in the direction of the cars motion. The car speeds up to 31.3 m/s. If

the force is applied for 5.4 s what is the magnitude of the force
Physics
1 answer:
vladimir1956 [14]2 years ago
3 0

The car accelerates with magnitude <em>a</em> such that

31.3 m/s = 25.6 m/s + <em>a</em> (5.4 s)

→   <em>a</em> = (31.3 m/s - 25.6 m/s) / (5.4 s) ≈ 1.056 m/s²

Then the applied force has a magnitude <em>F</em> of

<em>F</em> = (1430 kg) <em>a</em> ≈ 1500 N

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A block of mass 27.00 kg sits on a horizontal surface with, coefficient of kinetic
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The force is  F  = 172 \ N

Explanation:

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