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Vitek1552 [10]
4 years ago
14

Choose an example of a vertical motion with a negative velocity and a negative acceleration.

Physics
1 answer:
serious [3.7K]4 years ago
4 0

<u>Answer:</u>

  A body falling down towards earth, when upward direction is considered as positive direction got negative velocity and acceleration.

<u>Explanation:</u>

     You are standing on top of a building with certain height, H and you select height of building to be positive. If you throw a stone upward it's displacement is increasing and velocity is decreasing, both of them are positive and it is attracted towards earth by an acceleration so it is downward. SO it's value is negative.

   After reaching the maximum height the stone comes down and it's velocity increases in the downward direction, in this situation it is having negative velocity and and negative acceleration.

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8 0
3 years ago
If you could see the electric field coming off a proton you would notice that electric field lines are what?
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3 years ago
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3 0
3 years ago
Read 2 more answers
A 2kg box is pushed along a flat frictionless surface with an applied force of 53.91newton j+19.62 j were j is horizontal and j
tamaranim1 [39]

Since the box doesn't move vertically at all, no work is done by the vertical component of the force.

If 53.91 Newtons is the horizontal component of the force (very unclear in the question), then the work done is

<u>Work = (force) x (distance)</u>

Work = (53.91 N) x (10 m)

<em>Work = 539.1 Joules</em>

<u>Power = (work done) / (time to do the work)</u>

Power = (539.1 joules) / (90 sec)

Power = (539.1/90) (joule/sec)

<em>Power = 5.99 watts</em>

=====================================

Note:  If the mass of the box is only 2 kg, and you push it along the surface with a constant force of 53⁺ Newtons, and the surface really is frictionless, then that box is gonna cover a WHOOOOOLE LOT more than 10 meters in 90 seconds.  I get 109,168 meters !

5 0
4 years ago
Two identical cylindrical vessels with their bases at the same level each contain a liquid of density 1.23 g/cm3. The area of ea
motikmotik

Explanation:

Work done by gravity is given by the formula,

           W = \rho A (h_{1} - h)g (h - h_{2}) ......... (1)

It is known that when levels are same then height of the liquid is as follows.

           h = \frac{h_{1} + h_{2}}{2} ......... (2)

Putting value of equation (2) in equation (1) the overall formula will be as follows.

       W = \frac{1}{4} \rho gA(h_{1} - h_{2})^{2})

           = \frac{1}{4} \times 1.23 g/cm^{3} \times 9.80 m/s^{2} \times 3.89 \times 10^{-4} m^{2}(1.76 m - 0.993 m)^{2})

           = 0.689 J

Thus, we can conclude that the work done by the gravitational force in equalizing the levels when the two vessels are connected is 0.689 J.

3 0
3 years ago
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