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Vitek1552 [10]
4 years ago
14

Choose an example of a vertical motion with a negative velocity and a negative acceleration.

Physics
1 answer:
serious [3.7K]4 years ago
4 0

<u>Answer:</u>

  A body falling down towards earth, when upward direction is considered as positive direction got negative velocity and acceleration.

<u>Explanation:</u>

     You are standing on top of a building with certain height, H and you select height of building to be positive. If you throw a stone upward it's displacement is increasing and velocity is decreasing, both of them are positive and it is attracted towards earth by an acceleration so it is downward. SO it's value is negative.

   After reaching the maximum height the stone comes down and it's velocity increases in the downward direction, in this situation it is having negative velocity and and negative acceleration.

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A student of 4 feet tall went for swimming in a pool. He saw the depth of water in the pole less than 4 feet .Will he sink , wri
Nataly_w [17]

Answer:

he will not be drowned

Explanation:

Question says , the height of the student = 4 feet,

Depth of the pool( in feet ) be x ( say ) which is less than  4 feet,

Clearly, the depth of the pool < height of the student,

This means, if the student goes for swimming in the pool, however he does not know swimming, he will not be drowned until he is suffering from an injury or external force.

3 0
3 years ago
2. A hammer hits a nail with a force of 50 N into some wood. The area of the point of the nail is 0.02 cm2. What is the pressure
almond37 [142]

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6 0
3 years ago
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The electric field must be zero inside a conductor in electrostatic equilibrium, but not inside an insulator. It turns out that
pav-90 [236]

Answer:

The permittivity of rubber is  \epsilon  = 8.703 *10^{-11}

Explanation:

From the question we are told that

     The  magnitude of the point charge is  q_1 =  70 \ nC  =  70 *10^{-9} \  C

      The diameter of the rubber shell is  d = 32 \ cm  =  0.32 \ m

       The Electric field inside the rubber shell is  E =  2500 \ N/ C

The radius of the rubber is  mathematically evaluated as

              r =  \frac{d}{2} =  \frac{0.32}{2}  =  0.16 \ m

Generally the electric field for a point  is in an insulator(rubber) is mathematically represented as

         E =  \frac{Q}{ \epsilon }  *  \frac{1}{4 *  \pi r^2}

Where \epsilon is the permittivity of rubber

    =>     E  *  \epsilon  *  4 * \pi *  r^2 =  Q

   =>      \epsilon  =  \frac{Q}{E *  4 *  \pi *  r^2}

substituting values

            \epsilon  =  \frac{70 *10^{-9}}{2500 *  4 *  3.142 *  (0.16)^2}

            \epsilon  = 8.703 *10^{-11}

7 0
3 years ago
PLEASE HELP ME ON THIS ONE ANYONE
andreev551 [17]

Answer:

A & B

Explanation:

A & B Would be the right answer since Morse code cannot be represented through the height of the fire.

6 0
2 years ago
Please help please help
Inessa [10]

Answer: p= m/v so 90kg/.075m^3 = 1,200

2a. .35 m 1.1 m and .015 m

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volume= 57.75 m^3

Explanation: physics

6 0
3 years ago
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