Answer:
-150 kg m/s
Explanation:
The change of momentum is calculated as ;
Δp= m*Δv where
where
Δp= change in momentum
Δv = vf-vi
m= mass of the object
Change in momentum is also calculated when using the formula;
Δp = F * Δt when F is the net force applied and Δt is the time of action.
In this case;
m= 15 kg
vf= -10 m/s
vi= 0 m/s
Taking rightward direction to be positive, then leftward will be negative.
Applying the formula as;
Δp = m*Δv
Δp = 15 * { -10 -0} = 15*-10 = -150 kg m/s
Those are in a solid state.
Answer:
<u>411.84 kg m/s</u>
Explanation:
Formula :
<u>Momentum = mass × velocity</u>
<u />
=========================================================
Given :
⇒ mass = 26.4 kg
⇒ velocity = 15.6 m/s
=========================================================
Solving :
⇒ Momentum = 26.4 × 15.6
⇒ Momentum = <u>411.84 kg m/s</u>
So we want to know what is the magnitude of the horizontal component of acceleration ah if we know that the overall acceleration a=12 m/s^2 and the angle of overall acceleration and the horizontal acceleration is α=50°. We know that ah=a*cosα. So now it isn't hard to get the horizontal component: ah=12*cos50=12*0.64=7.71 m/s^2. So the correct answer is ah=7.71 m/s^2.
Answer:
The answer to your question is at the point where it is thrown.
Explanation:
Kinetic energy is the energy that possesses a body due to its motion. Its formula is
Ke = 1/2 mv²
Then, the kinetic energy is maximum when the velocity is the highest, and this is at the point where it is thrown, after this point, the velocity will be diminished and at the highest point will be equal to zero.
