The free-body diagram of a crate is shown.
2 answers:
The net force acting on the crate is the sum of all the forces acting in the different directions on the crate, which is 176N to the left.
- Upward force = 440 N
- Downward force = - 440N
- Rightward force = 176 N
- Leftward Force = - 352N
<u>The net vertical force acting on the crate</u> :
- Upward force + Downward force
- 440N + (-440N) = 0 N
<u>The net horizontal force acting on the crate</u> :
- Rightward force + Leftward force
- 176 N + (- 352 N) = - 176N
<u>The total net force acting on the crate</u> :
- Vertical + horizontal force
- 0 + (-176 N) = - 176 N
Therefore, the net force acting on the crate is - 176 N, which is 176 N to the left.
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Answer:
d = 0.38 m
Explanation:
As we know that the person due to the airbag action, comes to a complete stop, in 36 msec or less, and during this time, is decelerated at a constant rate of 60 g, we can find the initial velocity (when airbag starts to work), as follows:
vf = v₀ -a*t
If vf = 0, we can solve for v₀:
v₀ = a*t = 60*9.8 m/s²*36*10⁻³s = 21.2 m/s
With the values of v₀, a and t, we can find Δx, applying any kinematic equation that relates all of some of these parameters with the displacement.
Just for simplicity, we can use the following equation:
where vf=0, v₀ =21.2 m/s and a= -588 m/s².
Solving for d:
⇒ d = 0.38 m