All categories

1 year ago

The free-body diagram of a crate is shown.

2 answers:

4 0

The net force acting on the crate is the sum of all the forces acting in the different directions on the crate, which is 176N to the left.

Upward force = 440 N
Downward force = - 440N
Rightward force = 176 N
Leftward Force = - 352N

The net vertical force acting on the crate :

Upward force + Downward force
440N + (-440N) = 0 N

The net horizontal force acting on the crate :

Rightward force + Leftward force
176 N + (- 352 N) = - 176N

The total net force acting on the crate :

Vertical + horizontal force
0 + (-176 N) = - 176 N

Therefore, the net force acting on the crate is - 176 N, which is 176 N to the left.

Learn more :brainly.com/question/24119881

Angelina_Jolie [31]1 year ago

3 0

Answer:

B. is correct

Explanation:

EDGE2022

You might be interested in

A) Find the gravitational field strength of an asteroid with the mass of 3.2 * 10^3 kg and an average radius of 30 km when at a

MrMuchimi

a) $1.96\cdot 10^{-16} m/s^2$

The gravitational field strength near the surface of the asteroid is given by:

$g=\frac{GM}{(R+h)^2}$

where

G is the gravitational constant

M is the mass of the asteroid

R the radius of the asteroid

h is the distance from the surface

Substituting the data of the asteroid:

$M=3.2\cdot 10^3 kg$ is the mass

$R=30 km = 30000 m$ is the radius of the asteroid

$h=3 km = 3000 m$ is the distance from the surface

We find

$g=\frac{(6.67\cdot 10^{-11})(3.2\cdot 10^3)}{(30000+3000)^2}=1.96\cdot 10^{-16} m/s^2$

b) i) $5.53\cdot 10^9 s$

The acceleration of the astronaut popped out at 3 km from the surface is exactly that calculated at part a):

$g=1.96\cdot 10^{-16} m/s^2$

So, since its motion is at constant acceleration, we can find the time he takes to reach the surface using suvat equations:

$s=ut+\frac{1}{2}gt^2$

where

s = 3 km = 3000 m is his displacement to reach the surface

u = 0 is his initial velocity

t is the time

Solving for t,

$t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(3000)}{1.96\cdot 10^{-16} m/s^2}}=5.53\cdot 10^9 s$

b) ii) $1.08\cdot 10^{-6} m/s$

Again, we can use another suvat equation:

$v=u+gt$

where

v is the final velocity

u is the initial velocity

g is the acceleration of gravity

t is the time

Since we have

u = 0

$t=5.53\cdot 10^9 s$

$g=1.96\cdot 10^{-16} m/s^2$

The velocity of the astronaut at the surface will be

$v=0+(1.96\cdot 10^{-16} m/s^2)(5.53\cdot 10^9)=1.08\cdot 10^{-6} m/s$

b) iii) 175 years

The duration of one year here is

$T=3.16\cdot 10^7 s$

And the time it takes for the astronaut to reach the surface of the asteroid is

$t=5.53\cdot 10^9 s$

Therefore, to find the number of years, we just need to divide the total time by the duration of one year:

$n=\frac{t}{T}=\frac{5.53\cdot 10^9 s}{3.16\cdot 10^7}=175$

So, the astronaut will take 175 years to reach the surface.

8 0

3 years ago

Which vector should be negative?

Bas_tet [7]

The velocity of a falling object. In physics, down is regarded as a negative direction.

5 0

3 years ago

A copper wire (density equal to 8900 kg / m3) 0.3 mm in diameter "floats" due to the force of the earth's magnetic field, which

Andrews [41]

Answer: $I=112.094\ A$

Explanation:

Given

density $\rho =8900\ kg/m^3$

diameter $d=0.3\ mm$

Magnetic field $B=5.5\times 10^{-5}\ T$

Force on the current carrying conductor placed in a magnetic field

$F=BIL\sin \theta$

where L=length of conductor

$\theta$ =angle between magnetic field and current

If the wire is floating then weight must be balanced by weight of wire

$Weight=mg=\rho ALg$

Therefore

$\rho ALg=BIL\times \sin 90$

$8900\times \frac{\pi}{4}(0.3\times 10^{-3})^2L\times 9.8=5.5\times 10^{-5}\times I\times L$

$I=\frac{8900\times \pi\times 9\times 10^{-8}\times 9.8}{4\times 5.5\times 10^{-5}}$

$I=112.094\ A$

5 0

2 years ago

I need help in physics please help me

artcher [175]

The first step is to represent the vectors shown in the image in Cartesian coordinates.

For the vector C we have a magnitude of 4.8 and an angle 22 ° with the axis -y (direction j)

To write this vector in Cartesian coordinates we must find its component in x (address i) and in the y axis.

$x = 4.8sin(22)i\\\\y = 4.8cos(22)(-j)$

So:

$C = 4.8sin(22) i + 4.8cos(22)(-j)\\\\C = 1.798\ i - 4.450\ j$

For Vector B we have a magnitude of 5.6 and an angle of 33 with the -x axis (-i direction)

So:

$x = 5.6cos(33)(-i)\\\\y = 5.6 sin(33)(-j)$

So:

$B = 5.6cos(33)(-i) + 5.6sin(33)(-j)\\\\B = -4.696\ i - 3.05\ j$

Finally the sum of B + C is made component by component in the following way:

$F = (-4.696 +1.798)i + (-4.450 - 3.05)j\\\\F = -2.898\ i - 7.5\ j$

Finally the magnitude of f is:

$|F| = \sqrt{(-2,898)^2 + (-7.5)^2}$

| F | = 8.04

3 0

3 years ago

With its wheels locked, a van slides down a hill inclined at 40.0° to the horizonta l. Find the acceleration of this van A) if t

andreyandreev [35.5K]

Answer:

Explanation:

Check attachment for solution

7 0

3 years ago