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Kobotan [32]
3 years ago
15

A kayaker traveled 4 5/6 miles during the first hour, and 1 1/3 miles more then the next hour. How far did he travel in 2 hours

Mathematics
1 answer:
ss7ja [257]3 years ago
8 0

Answer:

11 miles

Step-by-step explanation:

Given that :

Distance traveled in first hour = 4 5/6 miles

Distance traveled in the next hour = 4 5/6 + 1 1/3

Therefore, the total distance traveled in 2 hours equals :

4 5/6 miles + (4 5/6 miles + 1 1/3 miles)

29/6 + 29/6 + 4/3

L. C. M of denominator = 6

(29 + 29 + 8) / 6

= 66 / 6 miles

= 11 miles

Distance traveled in 2 hours =. 11 miles

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jarptica [38.1K]

Answer:

X = 3/5

Step-by-step explanation:

2/x=4/5x+2

Find the LCM of the denominator 5x and 1

2/x =4/5x + 2/1

2/x = (4 + 10x)/5x

Cross multiply the equation

2× 5x = (4+ 10x) × x

10x = 4x + 10x^2

Collect like term of the mixed number

10x - 4x = 10x^2

6x = 10x^2

Divide both side by 2x

6x/2x = {10x^2 } / 2x

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Divide both side by the coefficient of x

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4 years ago
Ava and her little sister, April, both have the same birthdays on the same day. Ava is 12 years old, April is nine years old. Di
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Answer:

6 years ago

Step-by-step explanation:

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4 years ago
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A highway contractor owns heavy equipment which is used during the warm weather. During the winter months the equipment is to be
Kipish [7]

Answer:

a) 0.04

b) The choice of renting a protected area should be made

c) Indifference probability, P = 0.25

Step-by-step explanation:

a) Probability that the 25-year flood takes place in a given year.

This means that the flood is taking place once in 25 years, and the probability that it takes place in this given year is 1/25 = 0.04

b) The contractor is left with two alternatives, either to stay in protected area or flood plain area.

We will calculate the cost of staying in protected area and the loss incurred if he stays in the flood plain area. The one with the lesser value will be the more preferred decision.

Probability of a damaging flood, pr (flood) = 0.02

Probability of high damage if he chooses the flood plain = 0.5

Pr(high damage) = 0.02 * 0.5 = 0.01

Probability of low damage if he chooses the flood plain = 0.5

Pr(low damage) = 0.02 * 0.5 = 0.01

Loss(low damage) = $400,000

Loss(High damage) = %600,000

Average loss = [Pr(low damage)*Loss(low damage)] + [Pr(high damage) *Loss(High damage) ]

Average loss = (400000*0.01) + (600000*0.1)

Average loss = 4000 + 6000

Average loss = $10,000

Winter lasts for three months, i.e number of months = 3

Therefore the costs of renting the areas should be charged per month

Cost of renting flood plain = $10000 per year = 10000/12 = $833.22/month

Cost of renting protected area  = $35000 per month = 35000/12 = $2916.67/month

The protected area is not used

Cost of rent  for 1 month = $2916.67 - $833.22

Cost of rent for 1 month = $2083.45

Cost of renting protected area in 3 months = 3 * 2083.45 = $6250.34

Since the cost of renting protected area is less than the loss incurred in flood plain area, the contractor should rent a protected area

c)The principle of indifference states that in the absence of any relevant evidence, agents should distribute their credence equally among all the possible outcomes under consideration.

The probability of high or low damage = 0.50

Since there are just two options, and indifference does not assign probabilities based on prior information

Probability(flood) = 0.5

Probability that a flood with high damage will occur = Probability (flood) * Pr(high damage) = 0.5 * 0.5 = 0.25

Probability that a flood with low damage will occur = Probability (flood) * Pr(low damage) = 0.5 * 0.5 = 0.25

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suter [353]

Answer:

y = 9

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