All categories

3 years ago

10. (05.05 LC)

Mathematics

1 answer:

Mazyrski [523]3 years ago

5 0

Answer:

Step-by-step explanation:

You might be interested in

Plzzzzzzzzz help and fast

OverLord2011 [107]

A right skewed distribution/graph is the same as a positively skewed graph!

In this case, a right-skewed graph increases then decreases from left to right.

Your answer is B!

8 0

3 years ago

Find the volume of the composite solid. Round your answer to the nearest tenth.

alexira [117]

We need a picture of the shape.

3 0

3 years ago

Read 2 more answers

Fgh is first translated using the rule x,y >x+3,y-1this is followed by a 90 degrees counter clockwise rotation centered at th

maw [93]

Answer:

Rule:

$h = (1 - y,x + 3)$

Step-by-step explanation:

I will answer generally, since the coordinates of f, g and h are not given

Given

Point: x, y

Translation Rule

1 : x + 3, y - 1

2: 90 degree counterclockwise

Required

Determine the new coordinates

At the first translation of (x,y) by x + 3, y - 1

The new point is: $(x + 3, y - 1)$

At the second translation (90 degrees counterclockwise)

When a point (x,y) is translated using this rule, it becomes (-y,x)

So, the new point is:

$h = (-(y - 1),x + 3)$

$h = (1 - y,x + 3)$

If the initial point of h is (2,3),

The new point is:

$h = (1 - 3, 2 + 3)$

$h = (- 2, 5)$

5 0

3 years ago

Brent purchased a used vehicle that depreciates under a straight-line method. The initial value of the car is $7500, and the sal

Ilia_Sergeevich [38]

Let the value of the vehicle be described by the equation
V = a + bx
where x = number of years since purchase
a,b are constants.

When x = 0, V = $7500. Therefore
a + b*0 = 7500
a = 7500

When x = 7, V = $500. Therefore
7500 + 7b = 500
7b = 500 -7500 = -7000
b = -7000/7 = -1000

The equation is
V = 7500 - 1000x

The slope of this equation is the depreciation rate, and it is -$1000 per year.

Answer: $1000 depreciation per year.

5 0

4 years ago

Which function has a simplified base of 4RootIndex 3 StartRoot 4 EndRoot? f(x) = 2(RootIndex 3 StartRoot 16 EndRoot) Superscript

PIT_PIT [208]

Answer:

$f(x)=4\sqrt[3]{16}^{2x}$

Step-by-step explanation:

We believe you're wanting to find a function with an equivalent base of ...

$4\sqrt[3]{4}\approx 6.3496$

The functions you're looking at seem to be ...

$f(x)=2\sqrt[3]{16}^x\approx 2\cdot2.5198^x\\\\f(x)=2\sqrt[3]{64}^x=2\cdot 4^x\\\\f(x)=4\sqrt[3]{16}^{2x}\approx 4\cdot 6.3496^x\ \leftarrow\text{ this one}\\\\f(x)=4\sqrt[3]{64}^{2x}=4\cdot 16^x$

The third choice seems to be the one you're looking for.

9 0

3 years ago

Read 2 more answers