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Phoenix [80]
3 years ago
9

Who was the 43rd First Lady?

Physics
1 answer:
atroni [7]3 years ago
8 0

Answer: After serving as Second Lady from 1981 to 1989, Barbara Pierce Bush served as First Lady of the United States when her husband George H. W. Bush won the Presidency. She is also the mother of the 43rd President, George W. Bush, and of Florida's 43rd Governor, Jeb Bush.

Explanation:

You might be interested in
Name two everyday examples in which stored elastic potential energy is made use of. In each case state the energy transfer which
trasher [3.6K]

Answer:

A raised weight.

Water that is behind a dam.

Energy transfer takes place when energy moves from one place to another. Energy can move from one object to another, like when the energy from your moving foot is transferred to a soccer ball, or energy can change from one form to another.

Explanation:

7 0
3 years ago
A bowling bowl is thrown off the top of a building. Determine distance the ball has fallen after falling for 3.0 s. Remember, th
Zanzabum

d = distance the bowling ball has fallen = ?

g = acceleration due to gravity acting on the ball by earth = 9.8 m/s²

t = time of fall for the ball = 3.0 s

distance the ball has fallen is given as

d = (0.5) g t²

inserting the above values in the equation above

d = (0.5) (9.8 m/s²) (3.0 s)²

d = (0.5) (9.8 m/s²) (9.0 s²)

d = (4.9 m/s²) (9.0 s²)

d = 44.1 m

hence the distance fallen by the ball comes out to be 44.1 m

7 0
4 years ago
In this circuit (see picture), which resistor will draw the least power?
Basile [38]
A few different ways to do this: 

Way #1: 
The current in the series loop is  (12 V) / (total resistance) . 
(Turns out to be 2 Amperes, but the question isn't asking for that.)

In a series loop, the current is the same at every point, so it's
the same current through each resistor.

The power dissipated by a resistor is  (current)² · (resistance),
and the current is the same everywhere in the circuit, so the
smallest resistance will dissipate the least power.  That's  R1 .

And by the way, it's not "drawing" the most power.  It's dissipating it.

Way #2:
Another expression for the power dissipated by a resistance is

                 (voltage across the resistance)²  /  (resistance)  .

In a series loop, the voltage across each resistor is

          [ (individual resistance) / (total resistance ] x battery voltage.

So the power dissipated by each resistor is

         (individual resistance)² x [(battery voltage) / (total resistance)²]

This expression is smallest for the smallest individual resistance.
(The other two quantities are the same for each individual resistor.)
So again, the least power is dissipated by the smallest individual resistance.
That's R1 .                                      

Way #3:  (Einstein's way)
If we sat back and relaxed for a minute, stared at the ceiling, let our minds
wander, puffed gently on our pipe, and just daydreamed about this question
for a minute or two, we might have easily guessed at the answer.

===>  When you wire up a battery and a light bulb in series, the part
that dissipates power, and gets so hot that it radiates heat and light, is
the light bulb (some resistance), not the wire (very small resistance).
3 0
3 years ago
This is the science of extremely small structures and is leading to advanced materials, devices and applications in energy, medi
miv72 [106K]

Answer:

Nanotechnology

Explanation:

is this for that crossword puzzle lol

3 0
4 years ago
A two-liter bottle is one-fourth full of water and three-quarters full of air. The air in the bottle has a gage pressure of 340
Fantom [35]

Answer:

The value is     P_G  =  2.925 *10^{5} \  Pa

Explanation:

From the question we are told that

   The  volume of the bottle is  v  =  2 \  L  =  2 *  10^{-3} \  m^3

   The gauge pressure of the air is P_g  =  340 \  kPa  =  340 *10 ^{3}  \  Pa

   

Generally the volume of air before the bottle is turned upside down is  

      V_a  =  \frac{3}{4}  * V

       V_a  =  \frac{3}{4}  *  2 *10^{-3}

       V_a  =  0.0015 \  m^3 }

Generally the volume air when the bottle is turned upside-down is

      V_u  =  \frac{5}{6}  *  2 *10^{-3}

       V_u  =  0.00167 \  m^3

From the the mathematical relation of adiabatic process we have that

     P_g *  V_a^r  =  P_G *  V_u^r

Here r is a constant with  a value  r =  1.4

So

      340 *10 ^{3}  *  0.0015^{1.4}  =  P_G *  0.00167^{1.4}

        P_G  =  2.925 *10^{5} \  Pa

3 0
3 years ago
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