It depends on how fast you are going and in orincipal no
They don't need gas because satellites rotate around the world using our planet's gravitational force as centripetal force. That as well as since there is no air in space, it doesn't have to work against air resistance. This way it doesn't lose energy by going around and around the Earth.
Hope this helps, have a BLESSED day! :-)
Momentum = Mass × Velocity
From the given data, Mass is 1000kg and Velocity is 20m/s
Momentum = 1000 × 20
<span>(6.0x10^-22, -1.40x10^-21, 0) kg*m/s
Momentum is a conserved quantity. The total momentum of the system before and after the interactions will not change. So, let's look at the momentum before the interaction.
(3.2x10^-21, 0, 0) kg*m/s and (0,0,0) kg*m/s
After the interaction
(2.6x10^-21, 1.40x10^-21, 0) kg*m/s
and the other proton has to have a momentum that when added to this momentum equal the original value. Since the y and z vectors were initially 0, all we need for the y and x vector values of the result is to negate them. The x vector value will be
3.2x10^-21 - 2.6x10^-21 = 0.6x10^21 = 6.0x10^-22. So the other proton will have a momentum of
(6.0x10^-22, -1.40x10^-21, 0) kg*m/s</span>
