1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Fed [463]
3 years ago
14

An open-end mercury manometer is connected to a low-pressure pipeline that supplies a gas to a laboratory. Because paint was spi

lled on the arm connected to the line during a laboratory renovation, it is impossible to see the level of the manometer fluid in this arm. During a period when the gas supply is connected to the line but there is no gas flow, a Bourdon gauge connected to the line downstream from the manometer gives a reading of 7.5 psig. The level of mercury in the open arm is 900mm above the lowest part of the manometer.
(a) When the gas is not flowing, the pressure is the same everywhere in the pipe. How high above the bottom of the manometer would the mercury be in the arm connect to the pipe?
(b) When gas is flowing, the mercury level in the visible arm drops by 25mm. What is the gas pressure (psig) at thismoment?
Physics
1 answer:
almond37 [142]3 years ago
3 0

Answer:

A. Using

Pgauge= Pmanometer

And we know that

Pgauge= deta(hpg)

So deta h = Pgauge/density x g

So

= 7.5(6894.76/1psig)/ 13.6*10^3*9.8m/s²)

= 387.9mm

So to find height of pipe connected to the pipe we say

= h -deta h

= 900-387.97mm

=512.02mm

B. We use manometry principle

Pgas+density xg(25*10^3)-PX density{h-(H-0.25)=0

So

Finally Pgas= 6.54psig

You might be interested in
A pen rolls off a 0.55–meter high table with an initial horizontal velocity of 1.2 meters/second. At what horizontal distance fr
NARA [144]
To find the horizontal distance multiple the horizontal velocity by the time. Since there is no given time it must be calculated using kinematic equation.

Y=Yo+Voyt+1/2at^2
0=.55+0+1/2(-9.8)t^2
-.55=-4.9t^2
sqrt(.55/4.9)=t
t=0.335 seconds

Horizontal distance
=0.335s*1.2m/s
=0.402 meters
8 0
3 years ago
What is a satellite
g100num [7]

Answer:

an artificial body placed in orbit around the earth or moon or another planet in order to collect information or for communication.

Explanation:

Look it up on google

7 0
3 years ago
Read 2 more answers
A girl moves quickly to the center of a spinning merry-go-round, traveling along the radius of the merry-go-round. Which of the
DochEvi [55]

Answer:

The angular speed of the system increases.

The moment of inertia of the system decreases.

Explanation:

As we know that the girl is going towards the center of the circle so here the moment of inertia of the girl is given as

I = mr^2

here we know that

r = position of the girl from the center of the disc

now we know that the girl is moving towards the center so its distance will continuously decreasing

So the moment of inertia of the girl will decrease

Now we know that that with respect to the center of the disc there is no torque on the disc + girl system

So here we can use angular momentum conservation

So we have

I\omega = constant

since moment of inertia is decreasing for the system

so angular speed will increase

3 0
3 years ago
a guitar string is 0.620 m long, and oscillates at 234 Hz. if a player uses his finger to shorten the string to 0.480 m, what is
Nutka1998 [239]
Solve the x u will get 181.16

4 0
3 years ago
Read 2 more answers
Two satellites are orbiting earth at different altitudes. Which satellite orbits at a higher speed v around earth? Assume that t
alexandr1967 [171]

Answer:

a) the one with a lower orbit    b) the one with a higher  orbit

Explanation:

Let's consider orbital mechanics. To get an object in orbit, we need it to fall to earth parallel to the earth's surface. To understand it easily imagine a projectile thrown horizontally further and further away, at one point, the projectile hits the cannon from behind. Considering there is no wind resistance, that would be a projecile in orbit.

In other words, the circular orbits of some objects around a massive body are due to the equality between centrifugal acceleration and gravity acceleration.

\frac{v^2}{r} = \frac{GM}{r^2}.

so the velocity is

v = \sqrt{\frac{GM}{r} }

where "G" is the gravitational constant, "M" the mass of the massive body and "r" the distance between the object and the center of gravity of mass M. As you can note, if "r" increase, "v" decrease.

The orbital period of any object in orbit is

T = 2\pi \sqrt{\frac{a^3}{GM} }

where "a" is length of semi-major axis (a = r in circular orbits). So if "r" increase, "T" increase.

3 0
3 years ago
Other questions:
  • If pressure is increased from 200 kPa to 300 kPa, and the original volume of gas was 1.5 L, what is the new volume? Assume the t
    11·1 answer
  • To break a chemical bond, particles need to collide with a certain amount of a]energy. b]atoms. c]molecules. d]chemicals.
    9·1 answer
  • Which statement best defines work.
    6·1 answer
  • Recrystallization occurs in which type of rock
    9·2 answers
  • Isaac drop ball from height og 2.0 m, and it bounces to a height of 1.5 m what is the speed before and after the ball bounce?
    6·1 answer
  • In a chemical reaction, atoms are created or destroyed. True ore false...
    6·2 answers
  • What is the acceleration aaa of the refrigerator 4 ss after the person begins pushing on it with a force of 400 NN
    9·1 answer
  • What does the double arrow in the diagram below label?<br> ( click photo)
    7·1 answer
  • An athlete completes 1 laps around a track with a radius of 25 meters in 180 seconds. What is the magnitude of the athlete's tan
    9·1 answer
  • A typical laboratory centrifuge rotates at 4000 rpm. Testtubes have to be placed into a centrifuge very carefully because ofthe
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!