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egoroff_w [7]
3 years ago
8

Which expression could be used to solve this problem?

Mathematics
2 answers:
IRISSAK [1]3 years ago
8 0

Answer:

C. 3 x (20 + 15)

Step-by-step explanation:

You have to add 20 + 15 to get 45 so the 20 + 15 goes in the (). It says how much time he has practiced in 3 days so you have to multiply the things in the () by 3 so the 3 goes out side the ().

8090 [49]3 years ago
7 0

Answer:

C. 3 × (20 + 15)

Step-by-step explanation:

If Ben practices this way <em>every day</em>, then the amount of time should be the same.

20 minutes of song practice, 15 minutes of scale practice.

20+15=35

multiply the 35 minutes per day by three

35 times 3 equals 105

So the answer is C.

3 × (20 + 15)

<em>3(35)=105</em>

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Which table shows a non linear relationships between x and y
bazaltina [42]

Answer:

both of them thats the answer

Step-by-step explanation:

7 0
2 years ago
A toxic radioactive substance with a density of 2 milligrams per square centimeter is detected in the ventilating ducts of a nuc
Zolol [24]

Answer:

60.5 milligrams per square centimeter First, determine how many half lives have expired by dividing the time by the half-life. So: 55/20 = 2.75 That means that only 2^(-2.75) = 0.148650889 = 14.8650889% of the original substance remains. So just divide the amount remaining by 0.148650889 to get the original amount. 9 / 0.148650889 = 60.5445419 So originally, there was 60.5 milligrams per square centimeter 55 years ago.

3 0
3 years ago
Please help me with this !:(
ahrayia [7]

Answer:

75.062cm^{2}

Step-by-step explanation:

To find the missing side use pythagorean theorem

So 6^{2} +b^2=8.5^2

Solve for b, b= 6.021

To find the area use \frac{1}{2}bh

So \frac{1}{2}(6.021+19)(6)= area

And you get 75.062

7 0
3 years ago
3^sqrt -64w^12<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20-%2064w%5E%7B12%7D%7D%20" id="TexFormula1" title=" \s
Agata [3.3K]
-64=(-4)³, w^12=(w^4)³
the result is -4w^4
7 0
2 years ago
What is m to the power of 2 minus 11m minus 60 in product/sum method
Nana76 [90]

m^2 -11m -60 = 0

m^2 -11m =60

(m^2 -11m + 121/4) = 361/4

(m - 11/2)^2 = 361/4

m - 11/2 = + or - 19/2

m = 11/2 + 19/2, 11/2 - 19/2

m = 15, -4

---------------------------------------------------

m^2 -11m -60

(11 +- Square root (121 +240))/2

11/2 +- 19/2

m= 15, -4

----------------------------------------------------

m^2 -11m -60

(m - 15) (m + 4)

m = 15, -4

7 0
3 years ago
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